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-BARSIC- [3]
3 years ago
10

What is one important discovery that the curies made

Chemistry
1 answer:
tatiyna3 years ago
6 0
The Curies discovered radium
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Calculate Delta G for each reaction using Delta Gf values: answer kJ ...thank you
Leni [432]

Answer:

a) \Delta G=2.6kJ

b) \Delta G=-979.57kJ

c) \Delta G=264.21kJ

Explanation:

Hello,

In this case, in each reaction we must subtract the Gibbs free energy of formation the reactants to the Gibbs free energy of formation of the products considering each species stoichiometric coefficients. In such a way, the Gibbs free energy of formations are:

\Delta _fG_{H_2}=\Delta _fG_{I_2}=0kJ/mol\\\Delta _fG_{HI}=1.3kJ/mol\\\Delta _fG_{CO_2}=-394.4kJ/mol\\\Delta _fG_{CO}=-137.3 kJ/mol\\\Delta _fG_{NH_3}=16.7 kJ/mol\\\Delta _fG_{HCl}=-95.3kJ/mol\\\Delta _fG_{MnO_2}=465.37kJ/mol\\\Delta _fG_{Mn}=0kJ/mol\\\Delta _fG_{NH_4Cl}=-342.81kJ/mol

So we proceed as follows:

a)

\Delta G=2\Delta _fG_{HI}-\Delta _fG_{H_2}-\Delta _fG_{I_2}\\\\\Delta G=2*1.3\\\\\Delta G=2.6kJ

b)

\Delta G=\Delta _fG_{Mn}+2*\Delta _fG_{CO_2}-\Delta _fG_{MnO_2}-2*\Delta _fG_{CO}\\\\\Delta G=0+2*-394.4-465.37-2*-137.3\\\\\Delta G=-979.57kJ

c)

\Delta G=\Delta _fG_{NH_3}+\Delta _fG_{HCl}-\Delta _fG_{NH_4Cl}\\\\\Delta G=16.7-95.3-(-342.81)\\\\\Delta G=264.21kJ

Regards.

6 0
3 years ago
2.5 gm of a sample of Nahco3 when strongly.
mr_godi [17]

Answer:

Sry but i hope u will get the right answer and have a great christmas only 3 more days!

Explanation:

3 0
3 years ago
Calculate the density of air at 100 Deg C and 1 bar abs. Use the Ideal Gas Law for your calculation and give answer in kg/m3. Us
madam [21]

Answer:

d=0.92\frac{kg}{m^{3}}

Explanation:

Using the Ideal Gas Law we have PV=nRT and the number of moles n could be expressed as n=\frac{m}{M}, where m is the mass and M is the molar mass.

Now, replacing the number of moles in the equation for the ideal gass law:

PV=\frac{m}{M}RT

If we pass the V to divide:

P=\frac{m}{V}\frac{RT}{M}

As the density is expressed as d=\frac{m}{V}, we have:

P=d\frac{RT}{M}

Solving for the density:

d=\frac{PM}{RT}

Then we need to convert the units to the S.I.:

T=100^{o}C+273.15

T=373.15K

P=1bar*\frac{0.98atm}{1bar}

P=0.98atm

M=28.9\frac{kg}{kmol}*\frac{1kmol}{1000mol}

M=0.0289\frac{kg}{mol}

Finally we replace the values:

d=\frac{(0.98atm)(0.0289\frac{kg}{mol})}{(0.082\frac{atm.L}{mol.K})(373.15K)}

d=9.2*10^{-4}\frac{kg}{L}

d=9.2*10^{-4}\frac{kg}{L}*\frac{1L}{0.001m^{3}}

d=0.92\frac{kg}{m^{3}}

5 0
3 years ago
The ΔHsoln is _____.
nydimaria [60]

Sometimes negative sometimes positive, your answer is B!

4 0
3 years ago
HCl, NaCl, and CO are all examples of chemical <br> properties<br> bonds<br> formulas<br> changes
Ainat [17]

Answer:

HCL, NACL and CO are the examples of chemical formulas

4 0
3 years ago
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