Answer:
the solubility of CaCO3 is 0.015g/l 25 °C
is favored at equilibrium
Explanation:
The Ksp of calcium carbonate in water at 25 °C is 2.25 x 10-8. CaCO3(s) <----> Ca2+ (aq) + CO3 2- (aq) What is favored at equilibrium?
solubility is the property of a solute to dissolve in a solvent(liquid, gas ) to form a solution(soution can be saturated ,unsaturated, or supersaturated)
CaCO3(s) <----> Ca2+ (aq) + CO3 2- (aq)
in partial dissociation , we can say
2.25x 10^-8=
let Ca^2+=CO3^-2=S
2.25x10^-8=S*S
S^2=2.25x10^-8
S=0.00015mol/L
Converting that to g/l
the relative molecular mass of CaCO3=100g/mol
0.00015*100g/mol
0.015g/l
the solubility of CaCO3 is 0.015g/l @room temperature
is favored at equilibrium
I think its A because some scientist from the Department of Physics of Northeastern University found out that is not a part of Dalton's atomic theory.
The answer is A cause gas clouds hold elements in it
Answer:
Potassium (K) and Lithium (Li) for the fist one i cant see the second
Explanation:
Explanation:
Properties of a solution which are dependent on the ratio of number of solute particles to the number of solvent molecules in a solution are known as colligative properties.
Lowering of vapor pressure and elevation in boiling point are basically two of the colligative properties which indirectly help to measure the molecular weight of a substance.
Thus, we can conclude that molar mass of the solute can be determined by measuring lowering of vapor pressure and elevation in boiling point.
