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34kurt
3 years ago
6

By titration, it is found that 73.3 mL of 0.175 M NaOH(aq) is needed to neutralize 25.0 mL of HCl(aq). Calculate the concentrati

on of the HCl solution.
Chemistry
1 answer:
QveST [7]3 years ago
8 0

Answer:

0.5131M

Explanation:

NaOH(aq) + HCl(aq) — NaCl(aq) + H20(l)

Mole ratio of acid to base 1:1

(Ca × Va)/ (Cb × Vb) = Na/Nb

(0.175 × 73.3)/ (Cb × 25)= 1/1

12.8275= 25 × Cb

Cb= 12.8275/25

= 0.5131M

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