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2 years ago

Can someone help please? :)

Chemistry

1 answer:

Leno4ka [110]2 years ago

7 0

1) This is a definition.

2) Protons are given by the bottom number (since atomic number = number of protons).

3) Neutrons = (mass number)-(atomic number), which are the top and bottom numbers, respectively.

4) Nuclear fusion involves combining two things together, which is only reflected by the last option.

5) This is a fact.

6) This is a fact.

7) This is a fact.

8) This is a fact.

9) The correct option is the explanation.

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Esterification is what type of reaction?

lyudmila [28]

Esters and Formation of esters. Esters and water are formed when alcohols react with carboxylic acids. This reaction is called esterification, which is a reversible reaction. ... Since esterification is a reversible reaction, esters can undergo hydrolysis to form corresponding alcohol and organic acid.

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3 years ago

What does the equation A + BC to B + AC represent

katrin2010 [14]

<em>Displacement reactions</em>

6 0

3 years ago

Where is most of an atom's atomic mass?

Kamila [148]

Answer:

The nucleus contains the majority of an atom's mass because protons and neutrons are much heavier than electrons, whereas electrons occupy almost all of an atom's volume. The diameter of an atom is on the order of 10−10 m, whereas the diameter of the nucleus is roughly 10−15 m—about 100,000 times smaller.

Explanation:

3 0

2 years ago

Read 2 more answers

Use the data given below to construct a Born-Haber cycle to determine the heat of formation of KCl. Δ H°(kJ) K(s) → K(g) 89 K(g)

AURORKA [14]

Explanation:

The net equation will be as follows.

$K(s) + Cl_{2}(g) \rightarrow KCl(s)$

So, we are required to find $\Delta H_{formation}$ for this reaction.

Therefore, steps involved for the above process are as follows.

Step 1: Convert K from solid state to gaseous state

$K(s) \rightarrow K(g)$ , $\Delta H_{1}$ = 89 kJ

Step 2: Ionization of gaseous K

$K(g) \rightarrow K^{+}(g) + e^{-}$ , $H_{2}$ = 418 KJ

Step 3: Dissociation of $Cl_{2}$ gas into chlorine atom .

$\frac{1}{2} Cl_{2}(g) \rightarrow Cl(g)$ , $\Delta H_{3} = \frac{244}{2}$ = 122 KJ

Step 4: Iozination of chlorine atom.

$Cl(g) + e^{-} \rightarro Cl^{-}(g)$ , $H_{4}$ = -349 KJ

Step 5: Add $K^{+}$ ion and $Cl^{-}$ ion formed above to get KCl .

$K^{+}(g) + Cl^{-}(g) \rightarrow KCl(s)$ , $H_{5}$ = -717 KJ

Now, using Born-Haber cycle, value of enthalpy of the formation is calculated as follows.

$\Delta H_{f} = \DeltaH_{1} + \Delta H_{2} + \Delta H_{3} + \Delta H_{4} + \Delta H_{5}$

= 89 + 418 + 122 - 349 - 717

= - 437 KJ/mol

Thus, we can conclude that the heat of formation of KCl is - 437 KJ/mol.

5 0

3 years ago

Collisions only result in a reaction if the particles collide with a certain maximum energy called the activation energy of the

Alinara [238K]

Answer: The statement collisions only result in a reaction if the particles collide with a certain maximum energy called the activation energy of the reaction, is false.

Explanation:

Activation energy is the minimum amount of energy required to initiate a chemical reaction.

So, when activation energy for a reaction is lower then molecules with lower energy can also participate in the reaction. As a result, more number of collisions will take place due to which an increase in the rate of reaction will takes place.

When activation energy for a reaction is larger then molecules with higher energy will not be able to participate in the reaction. As a result, less number of collisions will take place due to which a decrease in rate of reaction will occur.

Therefore, we can conclude that the statement collisions only result in a reaction if the particles collide with a certain maximum energy called the activation energy of the reaction, is false.

4 0

2 years ago