Mass / volume = density
30.943g / 35ml = 0.88408571g/ml
Answer:
Part 1: 7.42 mL; Part 2: 3Cu²⁺(aq) + 2PO₄³⁻(aq) ⟶ 2Cu₃(PO₄)₂(s)
Explanation:
Part 1. Volume of reactant
(a) Balanced chemical equation.

(b) Moles of CuCl₂

(c) Moles of Na₃PO₄
The molar ratio is 2 mmol Na₃PO₄:3 mmol CuCl₂

(d) Volume of Na₃PO₄

Part 2. Net ionic equation
(a) Molecular equation

(b) Ionic equation
You write molecular formulas for the solids, and you write the soluble ionic substances as ions.
According to the solubility rules, metal phosphates are insoluble.
6Na⁺(aq) + 2PO₄³⁻(aq) + 3Cu²⁺(aq) + 6Cl⁻(aq) ⟶ Cu₃(PO₄)₂(s) + 6Na⁺(aq) + 6Cl⁻(aq)
(c) Net ionic equation
To get the net ionic equation, you cancel the ions that appear on each side of the ionic equation.
<u>6Na⁺(aq)</u> + 2PO₄³⁻(aq) + 3Cu²⁺(aq) + <u>6Cl⁻(aq)</u> ⟶ Cu₃(PO₄)₂(s) + <u>6Na⁺(aq)</u> + <u>6Cl⁻(aq)</u>
The net ionic equation is
3Cu²⁺(aq) + 2PO₄³⁻(aq) ⟶ Cu₃(PO₄)₂(s)
Answer:
1109 g H₂O
Explanation:
2.2 pounds can be converted to grams using a conversion ratio:
(2.2lb)(453.592g/lb) = 997.9024 g C₅₇H₁₁₀O₆
The mass in grams is converted to moles using the molecular weight of tristearin (891.48 g/mol)
(997.9024 g)(mol/891.48g) = 1.119...mol C₅₇H₁₁₀O₆
The moles of C₅₇H₁₁₀O₆ can be related to the moles of water through the molar ratio:
(1.119mol C₅₇H₁₁₀O₆)(110 H₂O/2 C₅₇H₁₁₀O₆) = 61.545 mol H₂O
The mass of water is then calculated using the molecular weight (18.02 g/mol):
(61.545 mol)(18.02 g/mol) = 1109 g H₂O