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3 years ago

A circle centered at the origin contains the point

Mathematics

1 answer:

nadezda [96]3 years ago

5 0

Answer: yes your correct it is c

Step-by-step explanation:

Did this online

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Does anybody have their geometry notebook for E2020? I need it to get credit for the course but I lost mine.

xxMikexx [17]

Answer:

Sorry, I don't have one.

Step-by-step explanation:

6 0

3 years ago

Malachi’s garden is 2 3/5 meters long. He wants to plant tomato plants every 1/5 of a meter. How many plants can Malachi fit?

Sophie [7]

2 3/5= 13/5
(13/5)/(1/5)=(13/5)5=13
answer: A maximum of 13 tomato plants :)

5 0

3 years ago

Read 2 more answers

HELP ME please i need to solve this

nata0808 [166]

add 0+1+2+3+4 = 10

divide 10÷5 = 2

add 15+8+3+3+1 = 30

divide 30÷5 = 6

the ratio is 2:6 which simplifies to 1:3 by the means of lates per student. In other words there is one late per 3 students.

5 0

3 years ago

What is (11-8)-2x6+32x56÷72?

Phantasy [73]

15.889 or 15.8888999 because when you solve the 8 and 9 is a rbeing repeated,

7 0

3 years ago

(Sketch the graph x^2-7x+12=0

Nonamiya [84]

Answer:

The graph in the attached figure

Step-by-step explanation:

we have

$x^{2} -7x+12=0$

This is a vertical parabola open upward (because the leading coefficient is positive)

The vertex is a minimum

step 1

Find the vertex of the quadratic equation

Convert the equation in vertex form

Complete the squares

$(x^{2} -7x+3.5^2)+12-3.5^2=0$

$(x^{2} -7x+12.25)+12-12.25=0$

$(x^{2} -7x+12.25)-0.25=0$

Rewrite as perfect squares

$(x-3.5)^{2}-0.25=0$

The vertex is the point (3.5,0.25)

step 2

Find the x-intercepts

The x-intercepts are the values of x when the value of the function is equal to zero

we have

$(x-3.5)^{2}-0.25=0$

solve for x

$(x-3.5)^{2}=0.25$

square root both sides

$(x-3.5)=\pm0.50$

$x=3.5\pm0.50$

$x=3.5+0.50=4$

$x=3.5-0.50=3$

therefore

The x-intercepts are the points (3,0) and (4,0)

step 3

Find the y-intercept

The y-intercept is the value of y when the value of x is equal to zero

we have

$y=x^{2} -7x+12$

For x=0

$y=(0)^{2} -7(0)+12$

$y=12$

The y-intercept is the point (0,12)

step 4

Graph the quadratic equation

we have

The vertex (3.5,0.25)

The x-intercepts (3,0) and (4,0)

The y-intercept (0,12)

using a graphing tool

Plot the points and draw the figure

The graph in the attached figure

3 0

3 years ago