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Ksivusya [100]
3 years ago
7

The lifting force generated by fluids on immersed objects is known as ____________.

Physics
1 answer:
Drupady [299]3 years ago
7 0
<span>The lifting force generated by fluids on immersed objects is known as <span>"Buoyant Force".

</span></span><span>and Buoyant force is equal in magnitude to the weight of the fluid displaced by the object.
</span>
So, in short, fill "Buoyant Force" in the blank!

Hope this helps!
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What happens to the compass needle as you move the compas<br> around the magnet?
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When you moved the compass near a bar magnet, the needle pointed toward the magnet's magnetic field and not toward the north.

Explanation:

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4. What relationship between gravitational
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(C) increases; decreases

Explanation:

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Which of the following is not a step in the inquiry process?
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Why must one use a reference point to determine whether or not an object is in motion
GaryK [48]
Because there's no such thing as "really" moving. 
ALL motion is always relative to something.

Here's an example:
You're sitting in a comfy cushy seat, reading a book and listening
to your .mp3 player, and you're getting drowsy.  It's so warm and
comfortable, your eyes are getting so heavy, finally the book slips
out of your hand, falls into your lap, and you are fast asleep.

-- Relative to you, the book is not moving at all.
-- Relative to the seat, you are not moving at all.
-- Relative to the wall and the window, the seat is not moving at all.
-- But your seat is in a passenger airliner.  Relative to people on the
    ground, you are moving past them at almost 500 miles per hour !
-- Relative to the center of the Earth, the people on the ground are moving
   in a circle at more than 700 miles per hour.  
-- Relative to the center of the Sun, the Earth and everything on it are moving
   in a circle at about 66,700 miles per hour ! 

How fast are they REALLY moving ?
There's no such thing.
It all depends on what reference you're using.

7 0
3 years ago
HELP ASAP!!!
miss Akunina [59]

Write each force in component form:

<em>v </em>₁ : 50 N due east   →   (50 N) <em>i</em>

<em>v</em> ₂ : 80 N at N 45° E   →   (80 N) (cos(45°) <em>i</em> + sin(45°) <em>j</em> ) ≈ (56.5 N) (<em>i</em> + <em>j</em> )

The resultant force is the sum of these two vectors:

<em>r</em> = <em>v </em>₁ + <em>v</em> ₂ ≈ (106.5 N) <em>i</em> + (56.5 N) <em>j</em>

Its magnitude is

|| <em>r</em> || = √[(106.5 N)² + (56.5 N)²] ≈ 121 N

and has direction <em>θ</em> such that

tan(<em>θ</em>) = (56.5 N) / (106.5 N)   →   <em>θ</em> ≈ 28.0°

i.e. a direction of about E 28.0° N. (Just to clear up any confusion, I mean 28.0° north of east, or 28.0° relative to the positive <em>x</em>-axis.)

4 0
3 years ago
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