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3 years ago

The phase of the moon you see depends on

Chemistry

1 answer:

Mariana [72]3 years ago

8 0

I'm pretty sure it's B (I took earth science 3 years ago so it might be wrong. Sorry if it is :/)

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Let us assume that fe(oh)2(s) is completely insoluble, which signifies that the precipitation reaction with naoh(aq) (presented

Yuki888 [10]

17.8 mL NaOH

Step 1. Write the chemical equation

Fe^(2+) + 2NaOH → Fe(OH)2 + 2Na^(+)

Step 2. Calculate the moles of Fe^(2+)

Moles of Fe^(2+) = 500 mL Fe^(2+) × [0.0230 mmol Fe^(2+)]/[1 mL Fe^(2+)]

= 11.50 mmol Fe^(2+)

Step 3. Calculate the moles of NaOH

Moles of NaOH = 11.50 mmol Fe^(2+) × [2 mmol NaOH]/[1 mmol Fe^(2+)]

= 23.00 mmol NaOH

Step 4. Calculate the volume of NaOH

Volume of NaOH = 23.00 mmol NaOH × (1 mL NaOH/1.29 mmol NaOH)

= 17.8 mL NaOH

3 0

3 years ago

The greater the [H*], the stronger the acid. True False

Law Incorporation [45]

Trueeeeeeeeeeeeeeeee!!!!!

4 0

3 years ago

I need help with Chemistry: Mole Conversion It must be answered in complete detail

Anni [7]

Answer:

As Per Given Information

Number of moles SO₂ ( Sulphur dioxide ) is 0.30

We 've been asked to find the number of atoms in given moles of Sulphur dioxide .

Value of Avogadro Number is 6.022 × 10²³ mol⁻¹

For finding the number of atoms we will use formale

$\underline{\boxed{\textbf{\textsf{ Number \: of \: atoms \: = Given \: moles \: . Avogadro \: number}}}}$

Putting the given value we obtain

$\sf \twoheadrightarrow \: Number \: of \: atoms \: = 0.30 \times 6.022 \times {10}^{ 23} \\ \\ \sf \twoheadrightarrow \: Number \: of \: atoms \: = \: 1.8066 \times {10}^{ 23} atoms$

So, the number of atoms in sulphur dioxide is 1.8066 × 10²³

8 0

2 years ago

2. Matt went to his friend’s party. He ate a big meal and drank a keg of beer. He felt heartburn after the meal and took Tums to

evablogger [386]

Answer:

390.85mL

Explanation:

Step 1:

Data obtained from the question.

Initial pressure (P1) = 780 torr

Initial volume (V1) = 400mL

Initial temperature (T1) = 40°C = 40°C + 273 = 313K

Final temperature (T2) = 25°C = 25°C + 273 = 298K

Final pressure (P2) = 1 atm = 760torr

Final volume (V2) =?

Step 2:

Determination of the final volume i.e the volume of the gas outside Matt's body.

The volume of the gas outside Matt's body can be obtained by using the general gas equation as shown below:

P1V1/T1 = P2V2/T2

780 x 400/313 = 760 x V2 /298

Cross multiply to express in linear form

313 x 760 x V2 = 780 x 400 x 298

Divide both side by 313 x 760

V2 = (780 x 400 x 298) /(313 x 760)

V2 = 390.85mL

Therefore, the volume of the gas outside Matt's body is 390.85mL

3 0

3 years ago

What is the difference between corrosive and flammable

castortr0y [4]

- Corrosive chemicals eat away and destroy things. Flammable things can be burned with fire.

3 0

3 years ago