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Katena32 [7]
3 years ago
14

A physical change differs from a chemical change in hat waste products are formed through chemical changes. true or false?

Chemistry
2 answers:
masha68 [24]3 years ago
4 0
I would say true :D I think
Semmy [17]3 years ago
3 0

The answer is false not true false I said I just got the question wrong it is FALSE. Thank you for your time.

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1. What volume is required to contain 100.0 mol O2 at STP?​
Colt1911 [192]

Answer:

The volume is 2238,6 L

Explanation:

We use the formula PV=nRT. The conditions STP are: 1 atm of pressure and 273K of temperature:

PV=nRT ---> V=(nRT)/P

V= 100 mol x 0,082 l atm/K mol x 273K/ 1 atm

<em>V=2238, 6L</em>

5 0
3 years ago
After an hour in the cooler the sodas get colder and the ice gets warmer. Which of the following explains these changes correctl
kompoz [17]
Because it’s called heat changes it and melts the ice
6 0
3 years ago
Kinetic energy and gravitational potential energy are both forms of which type
scoundrel [369]

Answer:

<em>C. Potential energy</em>

Explanation:

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8 0
3 years ago
When 1 mol of sodium nitrate, is dissolved in 1 cubic decimeter of water, 40 kJ of heat energy is absorbed. What is the drop in
vesna_86 [32]

Answer:

 1.0  ° C

Explanation:

The molar mass for Sodium Nitrate NaNO₃ = (23+14+(16×3)) = 85

Number of moles of NaNO₃  = mass of NaNO₃ /molar mass of NaNO₃

⇒ 17/85 = 1.38 moles

Since 1 mole of NaNO₃  dissolved in 1 cubic decimeter of water, 40 kJ of heat energy is absorbed.

when 1.38 mole of NaNO₃  dissolved in 1 cubic decimeter of water, x kJ of heat energy is absorbed..

Then; x kJ of 1.38 mole of NaNo₃ = 1.38 × 40 kJ  =55.2 kJ of heat absorbed.

Using the relation : Q = mcΔT  to determine the temperature drop ; we get:

55.2 = 17 × 4 (ΔT)

55.2  = 68 ΔT

ΔT= 0.8 ° C

ΔT ≅  1.0  ° C

Therefore, the drop in temperature when 17.0g of sodium nitrate is dissolved in 1 cubic decimeter of water is   1.0  ° C

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3 years ago
What is the most common workplace for people in the Finance cluster?
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<span>https://www.onetonline.org/find/career?c=6</span>
8 0
3 years ago
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