<span>2Na + Cl2 => 2NaCl
1 mol Na + 0.5 mol Cl2 => 1 mol NaCl</span>
Answer:
56.97kJ
Explanation:
1 mole of N2 reacts with 73.8kJ
0.772 mole of N2 reacts with xkJ
cross multiply
x= 0.772×73.8
=56.97kJ
Answer:
3.864 g of C₃H₆
Explanation:
The balanced equation for the reaction is given below:
2C₃H₆ + 9O₂ —> 6CO₂ + 6H₂O
From the balanced equation above,
2 moles of C₃H₆ reacted to produce 6 moles of CO₂
Next, we shall determine the number of mole of C₃H₆ that reacted to produce 0.276 mole of CO₂. This can be obtained as follow:
From the balanced equation above,
2 moles of C₃H₆ reacted to produce 6 moles of CO₂.
Therefore, Xmol of C₃H₆ will react to produce 0.276 moles of CO₂ i.e
Xmol of C₃H₆ = (2 × 0.276)/6
Xmol of C₃H₆ = 0.092 mole
Finally, we shall determine the mass of 0.092 mole of C₃H₆. This can be obtained as follow:
Mole of C₃H₆ = 0.092 mole
Molar mass of C₃H₆ = (12×3) + (6×1)
= 36 + 6
= 42 g/mol
Mass of C₃H₆ =?
Mass = mole × molar mass
Mass of C₃H₆ = 0.092 × 42
Mass of C₃H₆ = 3.864 g
Therefore, 3.864 g of C₃H₆ is needed for the reaction.
P₁V₁ = P₂V₂
Convert 473ml > L
(1atm)(1.00L) = (0.473L)P₂
Divide by (0.473L)
Solve for 2.11atm
