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Crank
3 years ago
14

Someone plz help me

Mathematics
1 answer:
e-lub [12.9K]3 years ago
6 0
I can’t see it’s blurry
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I’ll give you brainlest if you answer this correctly
BaLLatris [955]
No give it to now lol
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3 years ago
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Find the measure of angle ABC. Round to one decimal place.
Lady_Fox [76]
M<ABC= (AD+CE)/2=(100+45)/2=145/2
m<ABC=72° 30'
8 0
4 years ago
Franco's Pizza is selling their pizzas 35% cheaper than usual if a pizza normally cost $12 how much is it now
avanturin [10]

Answer:

New or current cost = 12 - 4.2 = $7.8

Step-by-step explanation:

Franco's Pizza is selling their pizzas 35% cheaper than usual. This is a discount on the normal cost. To get the amount it costs now, we will find the percentage of the discount on the original cost and subtract what we get from the original cost.

Discount = 35℅

Original cost of pizza is $12 (if a pizza normally cost $12).

So the discount in terms of dollars

= ℅ discount / 100 × normal cost of pizza

= 35 / 100 × 12 =0.35 × 12 = $4.2

New or current cost of pizza would be normal or original cost - the discount in dollars.

New or current cost = 12 - 4.2 = $7.8

4 0
3 years ago
I don't understand calculus at all bruh :/. I figured out some of this but I don't know it the answer is 0 or 2. Whoever figures
Lady_Fox [76]

Answer:

-2

Step-by-step explanation:

This one you just plug in 32 because there is no denominator of 0.

So as x goes to 32, y would go to 2 because 5rt32 = 2

<u>EDIT</u>

My bad, i didn't see it as -32. the answer would be -2 though I believe bc

5rt-32 = -2

8 0
3 years ago
The point (- square-root 2/2, square-root2/2 is the point at which the terminal ray of angle theta intersects the unit circle. W
Rufina [12.5K]

Answer: The value of cosine is \frac{-\sqrt{2}} {2} and the value of cotangent is -1.

Explanation:

The given point is (\frac{-\sqrt{2}} {2}},\frac{\sqrt{2}} {2}).

Since the x coordinate is negative and y coordinate is positive so the point must be lies in second quadrant.

The distance of the point from the origin is,

r=\sqrt{(\frac{-\sqrt{2}} {2}-0)^2+(\frac{\sqrt{2}} {2}-0)^2}

r=\sqrt{ \frac{2}{4}+\frac{2}{4}}

r=1

The given point is in the form of (a,b). So we get,

a=\frac{-\sqrt{2}} {2}

b=\frac{\sqrt{2}} {2}

The formula for cosine,

\cos \theta =\frac{a}{r}

\cos \theta =\frac{\frac{-\sqrt{2}} {2}}{1}}

\cos \theta =\frac{-\sqrt{2}} {2}}

The formula for cotangent,

\cot \theta =\frac{a}{b}

\cos \theta=\frac{\frac{-\sqrt{2}} {2}}{\frac{\sqrt{2}} {2}}

\cos \theta=-1

Therefore, the value of cosine is \frac{-\sqrt{2}} {2} and the value of cotangent is -1.

7 0
3 years ago
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