Answer:
Explanation:
Q = kA∆T/t
Q = heat flow
K is thermal conductivity in W/mK
K is thermal conductivity of the material in W/mK
∆T is change in temperature across the material
A is cross-sectional area in m²
d is thickness in m
k is thermal conductivity = 0.1 J/s/m.°C
A is area = 100 cm^2 = 100 cm^2 × (1 m/100 cm)^2 = 0.01 m^2
∆T is temperature difference = 100 °C
t is thickness = 2 cm = 2/100 = 0.02 m
Q = 0.1×0.01×100/0.02 = 5 J/s
In a day, there are 24×60×60 = 86,400 s
Heat flow in a day = 5 J/s × 86,400 s = 432,000 J
