3. Source 2 demonstrates the division in Congress into two as outlined in which document

A hot-air balloon is descending at a rate of 2.3 m>s when a pas- senger drops a camera. If the camera is 41 m above the groun

zheka24 [161]

Answer:

a) t = 2.64s

b) Vf = -28.7m/s

Explanation:

If the balloon is descending, the velocity is -2.3m/s. So the equation to describe the postion of the falling camera is:

$Y = Vo*t - \frac{g*t^{2}}{2}$

$-41 = -2.3*t - \frac{10*t^{2}}{2}$ Solving for t, we get:

t1 = -3.1s and t2 = 2.64s We discard the negative time and use the positive one.

The velocity of the camera will be:

Vf = Vo - g*t = -2.3 - 10*2.64 = -28.7m/s

6 0

3 years ago

When a car is traveling 120 km/h how many times more kinetic energy would it have than if it were

LekaFEV [45]

Answer: 9

Explanation:

Kinetic energy is the energy possessed by a moving object. It is measured in joules, and depends on the mass (m) of the object and the speed (v) by which it moves i.e K.E = 1/2 x mass x velocity^2

So, car is traveling 120 km/h

KE = 1/2x m x (120 km/h)^2

KE = 0.5 x m x 14400

KE1 = 7200m

So, car is traveling 40 km/h

KE = 1/2x m x (40 km/h)^2

KE = 0.5 x m x 1600

KE2 = 800m

Now, divide the value of kinetic energy obtained during 120 km/h by that obtained during 40 km/h

i.e 7200m / 800m

= 9

Thus, the kinetic energy will be 9 times more at a speed of 120 km/h than at 40 km/h

4 0

3 years ago

The n = 2 to n = 6 transition in the bohr hydrogen atom corresponds to the ________ of a photon with a wavelength of ________ nm

Colt1911 [192]

The energy levels of the hydrogen atom are quantized and their energy is given by the approximated formula
$E=- \frac{13.6}{n^2} [eV]$
where n is the number of the level.

In the transition from n=2 to n=6, the variation of energy is
$\Delta E=E(n=6)-E(n=2)=-13.6 ( \frac{1}{6^2}- \frac{1}{2^2} )[eV]=3.02 eV$
Since this variation is positive, it means that the system has gained energy, so it must have absorbed a photon.

The energy of photon absorbed is equal to this $\Delta E$ . Converting it into Joule,
$\Delta E=3.02 eV=4.84 \cdot 10^{-19}J$
The energy of the photon is
$E=hf$
where h is the Planck constant while f is its frequency. Writing $\Delta E=hf$ , we can write the frequency f of the photon:
$f= \frac{\Delta E}{h}= \frac{4.84 \cdot 10^{-19}J}{6.63 \cdot 10^{-34}m^2 kg/s}=7.29 \cdot 10^{14}Hz$

The photon travels at the speed of light, $c=3 \cdot 10^8 m/s$ , so its wavelength is
$\lambda = \frac{c}{f}= \frac{3 \cdot 10^8 m/s}{7.29 \cdot 10^{14}Hz}=4.11 \cdot 10^{-7}m=411 nm$

So, the initial sentence can be completed as:
The n = 2 to n = 6 transition in the bohr hydrogen atom corresponds to the "absorption" of a photon with a wavelength of "411" nm.

4 0

4 years ago

Read 2 more answers

A batter swings at a baseball. The action force is the bat hitting the ball with a force of 5N. The reaction force, however, can

dlinn [17]

This is false. The reaction force can be determined.

6 0

3 years ago

How do you know the speed of an electromagnetic wave in a vacuum?

ycow [4]

Electromagnetic waves need no matter to travel - they can travel through empty space (a vacuum). In a vacuum, all electromagnetic waves travel at approximately 3 x 108 m/s - which is the fastest speed possible. ...
Light traveling value through an optical Fibre is, 2 x 108 m/s. Hope that helps.

5 0

3 years ago