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andreyandreev [35.5K]
9 months ago
9

How is phosphorylation of glyceraldehyde 3-phosphate in the payment phase of glycolysis different from phosphorylation of glucos

e in the preparatory phase?
Chemistry
1 answer:
svet-max [94.6K]9 months ago
7 0

In the preparatory phase of glycolysis, two molecules of ATP are invested and the hexose chain is cleaved into two triose phosphates. During this, the phosphorylation of glucose and its conversion to glyceraldehyde-3-phosphate take place.  During this phase, the conversion of glyceraldehyde-3-phosphate to pyruvate and the coupled formation of ATP take place. Because Glucose is split to yield two molecules of D-Glyceraldehyde-3-phosphate, each step in the payoff phase occurs twice per molecule of glucose.

Glyceraldehyde 3-phosphate dehydrogenase Simultaneous oxidation and phosphorylation of G3P produce 1,3-bisphosphoglycerate (1,3-BPG) and nicotine adenine dinucleotide (NADH).

The divalent cation also affected the response of the enzyme from the endosperm and shoots to adenine nucleotides and inorganic pyrophosphate.

This phase is also called the glucose activation phase. In the preparatory phase of glycolysis, two molecules of ATP are invested and the hexose chain is cleaved into two triose phosphates. During this, the phosphorylation of glucose and its conversion to glyceraldehyde-3-phosphate take place. Steps 1, 2, 3, 4, and 5 together are called the preparatory phase.

For more information on phosphorylation click on the link below:

brainly.com/question/7465103

#SPJ4

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A cubic piece of metal measures 2.50 cm on each edge. If the metal is nickel, whose density is 8.90 g/cm3, what is the mass of t
madreJ [45]
Volume of cube = a³

2.50 * 2.50 * 2.50 =  15.625 cm³

Density = 8.90 g/cm³

mass = ??

m = D * V

m = 8.90 * 15.625

m = 139.0625 g

hope this helps!
6 0
3 years ago
An ion of a single pure element always has an oxidation number of ________. a. 1 b. magnitude equal to its atomic number c. 0 d.
harina [27]

The oxidation state of a pure element is always zero.

The oxidation state for a pure ion is equivalent to its ionic charge.

What is oxidation state?

The oxidation state or oxidation number, is the hypothetical charge of an atom if all of its bonds to different atoms were fully ionic. The oxidation state may be positive, negative or zero.

What are the rules to write the oxidation number?

1. The atoms in pure elements have oxidation number of ZERO.

2. The more-electronegative element in a binary molecular compound is assigned the number equal to the negative charge it would have as an anion. The less-electronegative element is assigned the number equal to the positive charge it would have as a cation.

3. Fluorine always has an oxidation number of -1 in compounds because it is the most electronegative element.

4. Oxygen is usually -2 unless in peroxides (then it is -1) or with fluorine.

5. Hydrogen has +1 in all compounds containing elements that are more electronegative than it, and is -1 in compounds with metals.

6. The algebraic sum of the oxidation numbers of all atoms in a neutral compound is zero.

7. The algebraic sum of the oxidation numbers of all atoms in a polyatomic ion is equal to the charge of the ion.

8. Although rules 1-7 apply to covalently bonded atoms, oxidation numbers can also be assigned to atoms in ionic compound. Monoatomic ions have oxidation numbers equal to their ionic charge.

To learn more about oxidation number: brainly.com/question/3035498

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6 0
1 year ago
The light emitted from a flame is produced when electrons in an excited state
sesenic [268]
Electrons in their ground state when excited absorb energy and move to higher energy states.
Absorption is when energy is absorbed by electrons and they move to a higher energy state
Emission is when electrons release that absorbed energy and move to a lower energy state
This release of energy results in emission of light from a flame
The correct answer is
Release energy as they move to lower energy states
7 0
2 years ago
Read 2 more answers
For each pair of bonds, indicate the more polar bond, and use an arrow to show the direction of polarity in each bond.a. C-O and
Naddika [18.5K]

Answer:

The more polar bond is C-O.

Explanation:

The greater polarity is due to that the Oxygen atom is more electronegative than the Nitrogen atom, so the negativity of the molecule tends to be on that side.

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Answer: me

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