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ollegr [7]
3 years ago
12

The electrolyte that is used to make Hypochlorous Acid is made from Sodium Chloride (NaCl). the bottle says that the electrolyte

solution contains 25% sodium chloride. If 2.4 ounces of the solution is added to the half gallon to prepare for the reaction. How many total grams of sodium chloride are used in the reaction. If the reaction produces 1100 PPM of HOCl (hypocholorus acid) how many grams of Hypocholrous are made? Do you think all the NaCl was converted to HOCl? or we can brew one more time and get more HOCl. If all of the NaCl converts to HOCl what would be the maximum possible PPM of the disinfectant
Chemistry
1 answer:
kumpel [21]3 years ago
7 0

Answer:

63.9 grams. Yes, the Nacl was converted.  Maximum possible ppm is 540ppm.

Explanation:

I this is college level chemistry not regular high school chem.  

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What is radiation exactly
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radiation is energy that comes from a source. (travels through the speed of light)

6 0
3 years ago
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Select the correct value for the indicated bond angle in each of the following compounds: O-S-O angle of SO2 F-B-F angle of BF3
Stels [109]

Answer:

(A) O-S-O bond angle of SO₂ molecule = 119°

(B) F-B-F bond angle of BF₃ molecule = 120°

(C) Cl-S-Cl bond angle of SCl₂ molecule = 103°

(D) O-C-O bond angle of CO₂ molecule = 180°

(E) F-P-F bond angle of PF₃ molecule = 96.3°

(F) H-C-H bond angle of CH₄ molecule = 109.5°

Explanation:

Bond angle refers to the angle between two adjacent chemical bonds in a molecule. The bond angle is different for different molecular geometry.

The Valence shell electron pair repulsion theory predicts the molecular geometry and shape of the given molecule by the number of lone pairs on central atom and number of atoms bonded to central atom.

(A) SO₂ molecule

The number of atoms bonded to S = 2

Number of lone pairs on S = 1

<u>Therefore, the shape of SO₂ molecule is bent and the O-S-O bond angle is 119°.</u>

(B) BF₃ molecule

The number of atoms bonded to B = 3

Number of lone pairs on B = 0

<u>Therefore, the shape of BF₃ molecule is trigonal planar and the F-B-F bond angle is 120°.</u>

(C) SCl₂ molecule

The number of atoms bonded to S = 2

Number of lone pairs on S = 2

<u>Therefore, the shape of SCl₂ molecule is bent and the Cl-S-Cl bond angle is 103°.</u>

(D) CO₂ molecule

The number of atoms bonded to C = 2

Number of lone pairs on C = 0

<u>Therefore, the shape of CO₂ molecule is linear and the O-C-O bond angle is 180°.</u>

(E) PF₃ molecule

The number of atoms bonded to P = 3

Number of lone pairs on P = 1

<u>Therefore, the shape of PF₃ molecule is trigonal pyramidal and the F-P-F bond angle is 96.3°.</u>

(F) CH₄ molecule

The number of atoms bonded to C = 4

Number of lone pairs on C = 0

<u>Therefore, the shape of CH₄ molecule is tetrahedral and the H-C-H bond angle is 109.5°.</u>

7 0
3 years ago
Which salt is produced when copper oxide reacts with hydrochloric acid?
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It forms copper chloride
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3 years ago
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Consider the following reaction.
Ivan

Answer:

162 g Fe₂O₃

Explanation:

To find the mass of Fe₂O₃, you need to (1) convert grams C to moles C (via molar mass from periodic table), then (2) convert moles C to moles Fe₂O₃ (via mole-to-mole ratio from reaction coefficients), and then (3) convert moles Fe₂O₃ to grams (via molar mass). It is important to arrange the ratios/conversions in a way that allows for the cancellation of units. The final answer should have 3 sig figs to reflect the given value.

Molar Mass (C): 12.011 g/mol

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Molar Mass (Fe₂O₃): 2(55.845 g/mol) + 3(15.998 g/mol)

Molar Mass (Fe₂O₃): 159.684 g/mol

18.3 g C           1 mole            2 moles Fe₂O₃          159.684 g
--------------  x  ----------------  x  -------------------------  x  -----------------  = 162 g Fe₂O₃
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5 0
2 years ago
A sample of an ionic compound NaA, where A- is the anion of a
vitfil [10]

Answer:

a) Kb = 10^-9

b) pH = 3.02

Explanation:

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[NaA] and [A-] = 0.05/0.6 = 0.083 M

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b) For the stoichiometric point in the titration, 0.100 moles of NaA have to be found in a 1.1L solution, and this is equal to:

[A-] = [H+] = (0.1 L)*(1 M)/1.1 L = 0.091 M

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Ka = 10^-5 = ([H+]*[A-])/[HA] = [H+]^2/(0.091 - [H+])

[H+]^2 + 10^5 * [H+] - 10^-5 * 0.091 = 0

Clearing [H+]:

[H+] = 0.00095 M

pH = -log([H+]) = -log(0.00095) = 3.02

6 0
3 years ago
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