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<h3>First we find out the freezing point:</h3>→(-23.0)-(0.0_
→-23.0 degrees C
<h3>Calculate target Colligative Molarity:</h3>→ -23=1.86 * Cm
→ 12.37= Cm.
→i* molality
→i= 1
→12.37= 1*m
→12.37= m
<h3>molality= moles of solute(C2H6O2)/kg of solvent water</h3>12.37m= moles C2H6O2/ 10.0kg water
123.7= moles of C2H6O2
123.7moles C2H6O2 * 62.26g C2H6O2
<h2>= 7701.56 g of C2H6O2</h2>━┈─────────────────────┈━
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