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fiasKO [112]
3 years ago
9

How do you turn a proportionality between variables into an equation?

Chemistry
1 answer:
m_a_m_a [10]3 years ago
3 0

Answer. By adding the proportionality constant .

Explanation:

suppose '<em>x' a  </em>is directly proportional to the<em> 'y' , </em>where<em> x </em>and <em>y </em>are variables:

<em>x </em>∝ <em>y</em>

with an input of constant value 'K' proportionality relation gets converted into  an equation:

<em>x = </em>K <em>y</em>

For example : Gravitational force is directly proportional to the product of two masses and inversely proportional to the square of the distance between the two masses.

F ∝ \frac {m_1m_2}{r^{2}}

To convert this proportionality relation constant 'G'  was introduced known as gravitational constant whose value remains constant under every conditions.

F=\frac {G\times m_1m_2}{r^{2}}

G=6.67408\times 10^{-11}m^3Kg^{-1}s^{-2}



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How many grams of material is lost in the aqueous phase if two extractions are carried out on 100 mL of a 5% (m/v) aqueous solut
san4es73 [151]

Answer:

4.94g of material

Explanation:

Partition coefficient (Kp) of a substance is defined as the ratio between concentration of organic solution and aqueous solution, that is:

Kp = <em>8 = Concentration in Ethyl acetate / Concentration in water</em>

100mL of a 5% solution contains 5g of material in 100mL of water. Thus:

8 = X / 100mL / (5g-X) / 100mL

<em>Where X is the amount of material in grams that comes to the organic phase.</em>

8 = X / 100mL / (5g-X) / 100mL

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<em>Thus, in the first extraction you will lost 4.44g of material from the aqueous phase.</em>

And will remain 5g-4.44g = 0.56g.

In the second extraction:

8 = X / 100mL / (0.56g-X) / 100mL

8 = 100X / (56-100X)

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0.50g = X

<em>In the second extraction, you will extract 0.50g of material</em>

Thus, after the two extraction you will lost:

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<em></em>

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