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Morgarella [4.7K]
3 years ago
14

A plant worker accidentally breathes some stored gaseous tritium, a beta emitter with maximum particle energy of 0.0186 MeV. The

energy absorbed by the lungs, which have a total weight of l kg, is 4 x 10^-3 J. How many milli-rems dose equivalent was received?
Physics
1 answer:
andrey2020 [161]3 years ago
8 0

Answer:

400 milli-rems

Solution:

As per the question;

Maximum energy of particle, E_{m} = 0.0186\ MeV

Weight, w = 1 kg

Energy absorbed, E = 4\times 10^{- 3}\ J

Now,

Equivalent dose is given by:

D_{eq} = \frac{E}{w}  =\frac{4\times 10^{- 3}}{1} = 4\times 10^{- 3}\ J/kg

1 Gy = 1 J/kg

Also,

1 Gy = 1\times 10^{5}\ milli-rems

Therefore,

Dose equivalent in milli-rems is given by:

D_{eq} = 4\times 10^{- 3}\times 1\times 10^{5} = 400\ milli-rems

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