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Olenka [21]
3 years ago
15

In water, acids form _____.

Physics
2 answers:
Amiraneli [1.4K]3 years ago
8 0
The answer is hydrogen ions
NeTakaya3 years ago
7 0

<em>Answer:</em>

<em>D.)hydrogen ions</em>

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Please Help!!!
Alborosie

Answer:

D

Explanation:

5 0
3 years ago
At this rate, what fraction of its mass would io lose in 4. 5 billion years?.
Pie

In 4.5 billion years, the amount of mass lost is 1.41912 * 10¹⁷ kg.

<h3>Equation</h3>

An equation is an expression used to show the relationship between two or more variables and numbers.

Given that:

Io loses about a ton (1000 kilograms) of sulfur dioxide per second to Jupiter's magnetosphere.

In 4.5 billion years, amount of mass lost = 1000 kg/s * (4.5 * 10⁹ * 365 * 60 60 * 24) = 1.41912 * 10¹⁷ kg.

In 4.5 billion years, the amount of mass lost is 1.41912 * 10¹⁷ kg.

Find out more on Equation at: brainly.com/question/13763238

4 0
2 years ago
Electric field shows the strength and what of an electric field
Nikolay [14]

Answer:

a region in which particles with an electric charge will experience a force

Explanation:

let me know if its wrong . sorry if it is

4 0
3 years ago
Read 2 more answers
anyone know where I can find stuff (answer key, tables, etc.) for my Newton's Law of Motion lab report on edge2020? need answers
Zolol [24]
Usually the full tables are found on quizlet or quizzes
7 0
3 years ago
A block of ice(m = 14.0 kg) with an attached rope is at rest on a frictionless surface. You pull the block with a horizontal for
nadezda [96]

Answer:

a) The weight and the normal force of the block has a magnitude of 137.298 newtons and the pull force exerted on the block has a magnitude of 98 newtons.

b) The final speed of the block of ice is 9.8 meters per second.

Explanation:

a) We need to calculate the weight, normal force from the ground to the block and the pull force. By 3rd Newton's Law we know that normal force is the reaction of the weight of the block of ice on a horizontal.

The weight of the block (W), measured in newtons, is:

W = m\cdot g (1)

Where:

m - Mass of the block of ice, measured in kilograms.

g  - Gravitational acceleration, measured in meters per square second.

If we know that m = 14\,kg and g = 9.807\,\frac{m}{s^{2}}, the magnitudes of the weight and normal force of the block of ice are, respectively:

N = W = (14\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)

N = W = 137.298\,N

And the pull force is:

F_{pull} = 98\,N

The weight and the normal force of the block has a magnitude of 137.298 newtons and the pull force exerted on the block has a magnitude of 98 newtons.

b) Since the block of ice is on a frictionless surface and pull force is parallel to the direction of motion and uniform in time, we can apply the Impact Theorem, which states that:

m\cdot v_{o} +\Sigma F \cdot \Delta t = m\cdot v_{f} (2)

Where:

v_{o}, v_{f} - Initial and final speeds of the block, measured in meters per second.

\Sigma F - Horizontal net force, measured in newtons.

\Delta t - Impact time, measured in seconds.

Now we clear the final speed in (2):

v_{f} = v_{o}+\frac{\Sigma F\cdot \Delta t}{m}

If we know that v_{o} = 0\,\frac{m}{s}, m = 14\,kg, \Sigma F = 98\,N and \Delta t = 1.40\,s, then final speed of the ice block is:

v_{f} = 0\,\frac{m}{s}+\frac{(98\,N)\cdot (1.40\,s)}{14\,kg}

v_{f} = 9.8\,\frac{m}{s}

The final speed of the block of ice is 9.8 meters per second.

6 0
3 years ago
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