The Inertia is 22. 488 kg. m² and the speed just before it hits the ground is 6. 4 m/s
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How to determine the inertia</h3>
Using the formula:
I = 1/2 M₁R₁² + 1/2 M₂R₂²
Where I = Inertia
I = 1/2 * 0.810* (2. 60)² + 1/2 * 1. 58 * (5)²
I = 1/2 * 5. 476 + 1/2 * 39. 5
I = 2. 738 + 19. 75
I = 22. 488 kg. m²
To determine the block's speed, use the formula
v = 
v = 
v = 
v = 6. 4 m/s
Therefore, the Inertia is 22. 488 kg. m² and the speed just before it hits the ground is 6. 4 m/s
Learn more about law of inertia here:
brainly.com/question/10454047
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You divide 120 from 950 and that's the number of hours, 7.9
Answer:
u= 20.09 m/s
Explanation:
Given that
m = 0.02 kg
M= 2 kg
h= 0.2 m
Lets take initial speed of bullet = u m/s
The final speed of the system will be zero.
From energy conservation
1/2 m u²+ 0 = 0+ (m+M) g h
m u²=2 (m+M) g h
By putting the values
0.02 x u² = 2 (0.02+2) x 10 x 0.2 ( take g=10 m/s²)
u= 20.09 m/s