The answer is true I did that test befor
The maximum height at which the baseball will reach is given by the formula
<span>Vf^2 - Vo^2 = 2gh </span>
<span>where </span>
<span>Vf = final velocity = 0 (at its peak) </span>
<span>Vo = initial velocity = 22 m/sec (given) </span>
<span>g = acceleration due to gravity = 9.8 m/sec^2 (constant) </span>
<span>h = maximum height attained by the ball </span>
<span>Substituting appropriate values, </span>
<span>0 - (22)^2 = 9(-9.8)h </span>
<span>NOTE the negative sign attached to the acceleration due to gravity. This simply denotes that the ball is slowing down as it goes up. </span>
<span>Solving for "h", </span>
<span>h = 22^2/(2 * 9.8) </span>
<span>h = 24.69 meters </span>
<span>To solve for the time it reaches its maximum height, use the formula </span>
<span>h = VoT -(1/2)(gT^2) </span>
<span>where </span>
<span>T = time for ball to reach maximum height </span>
<span>and all the other terms have been previously defined. </span>
<span>Substituting values, </span>
<span>24.69 = 22T - (1/2)(9.8)T^2 </span>
<span>Rearranging the above, </span>
<span>4.9T^2 - 22T + 24.69 = 0 </span>
<span>Using the quadratic formula, </span>
<span>T = 2.22 seconds </span>
<span>NOTE --- the above is the time for the ball to reach its maximum height. The total time it is in the air is </span>
<span>Total time = 2(2.22) = 4.44 sec.
Hope this helps :) </span>
Correct Answer: Option C
<em>Explanation
</em>
X = ut + 12at2
= (0 x 4) + (12 x 0.1 x 4 x 4)
= 0.8m
workdone = force x distance
= 40 x 0.8
= 32J