Question

The force of attraction between a -130.0 C and +180.0 C charge is 8.00 N. What is the separation between these two charges in meter rounded to three decimal places? (k = 1/470 - 9.00 10°N.m2/C2 1uC = 106C)

Answer 1

Answer with Explanation:

The force of attraction between 2 charges of magnitude$q_1,q_2$ separated by a distance 'r' is given by

$F=\frac{1}{4\pi \epsilon _o}\frac{q_1\times q_2}{r^2}=k\frac{q_1\times q_2}{r^2}$

where

$\epsilon _o$ is a constant known as permitivity of free space

$k=9\times 10^{9}Nm^2/C^2$

Applying the given values in the above relation we get

$8=9\times 10^{9}\times \frac{130\times 180}{r^{2}}\\\\r^{2}=\frac{9\times 10^{9}\times 130\times 180}{8}\\\\r^{2}=26325\times 10^{9}\\\\\therefore r=\sqrt{26325\times 10^{9}}=5.131\times 10^{6}meters$