When 1 carbon atom combines with 2 oxygen atoms, the resulting substance is carbon dioxide which is a Compound. Hope this helps.
Savannah (:
Answer:
as
- Mass of sun > Mass of earth
Therefore, the sun will exert more gravitational force on earth.
Explanation:
While comparing the gravitational force exerted by two objects, we need to observe which object has a greater mass.
- The object with the greater mass exerts a more gravitational force on the other object.
We know that mass of the sun is about 1.99 x 10³⁰ kg, and the earth's mass is only 6.0 x 10²⁴.
as
- Mass of sun > Mass of earth
Therefore, the sun will exert more gravitational force on earth.
The net force on q2 will be 1.35 N
A force in physics is an effect that has the power to alter an object's motion. A mass-containing object's velocity can vary, or accelerate, as a result of a force. Intuitively, a push or a pull can also be used to describe force. Being a vector quantity, a force has both magnitude and direction.
Given Particles q1, q2, and q3 are in a straight line. Particles q1 = -5.00 x 10-6 C,q2 = +2.50 x 10-6 C, and q3 = -2.50 x 10-6 C. Particles q₁ and q2 are separated by 0.500 m. Particles q2 and q3 are separated by 0.250 m.
We have to find the net force on q2
At first we will find Force due to q1
F = 9 × 10⁹ × 5 × 10⁻⁶ × 2.5 × 10⁻⁶ / 0.5²
F = 450 × 10⁻³
F₁ = 0.45 N (+)
Now we will find Force due to q2
F = 9 × 10⁹ × 5 × 10⁻⁶ × 2.5 × 10⁻⁶ / 0.25²
F = 1800 × 10⁻³
F₂ = 1.8 N (-)
So net force (F) will be
F = F₂ - F₁
F = 1.8 - 0.45
F = 1.35 N
Hence the net force on q2 will be 1.35 N
Learn more about force here:
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Answer:
1500 per second.
Explanation:
vibrations = 1.5 kilohertz
1.5×1000=1500
the answer is 1500 per second.
Answer:
34.70 N
Explanation:
Given :
F~ 1 = 43 N in direction 38◦
F~ 2 = 26 N in direction −140◦
F~ 3 = 27 N in direction 110◦
Therefore,
F~x = 43 cos (38) + 26 cos (-140) + 27 cos (110)
= 43 (0.7) + 26 (-0.7) + 27 (-0.3)
= 3.8
F~y = 43 sin (38) + 26 sin (-140) + 27 sin (110)
= 43 (0.6) + 26 (-0.6) + 27 (0.9)
= 34.5
so, F~ = 
= 34.70 N
