Please help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

It takes 52,000 Joules to heat a cup of coffee to boiling from room temperature. How long a piece of 20 cm wide Aluminum foil wo

vovikov84 [41]

Answer:

L = 1.11 x $10^{6}$ m, is the length of piece of 20 cm wide Aluminum foil to make capacitor large enough to hold 52000 J of energy.

Explanation:

Solution:

Data Given:

Heat Energy = 52000 J

Dielectric Constant of the plastic Bag = 3.7 = K

Thickness = 2.6 x $10^{5}$ m =d

V = 610 volts

A = width x Length

width = 20 cm = 20 x $10^{-2}$ m

Length = ?

So,

we know that,

U = 1/2 C Δ $v^{2}$

U = 52000 J

C = ?

V = 610 volts'

So,

U = 1/2 C Δ $v^{2}$

52000 J = (0.5) x (C) x ( $610^{2}$ )

C = 0.28 F

And we also know that,

C = $\frac{K*E*A}{d}$

E = 8.85 x $10 ^{-12}$

K = 3.7

A = 0.20 x L

d = 2.6 x $10^{5}$ m

Plugging in the values into the formula, we get:

0.28 = $\frac{3.7 * 8.85 .10^{-12} * (0.20 . L) }{2.6 . 10^{5} }$

Solving for L, we get:

L = 1.11 x $10^{6}$ m,

is the length of piece of 20 cm wide Aluminum foil to make capacitor large enough to hold 52000 J of energy.

7 0

3 years ago

The current perception of the arrangement of an atom is represented in the picture at right.

yarga [219]

Answer:

theroy

Explanation:

6 0

3 years ago

A string, 30 cm long and having a mass of 45 g, is attached to a 810 Hz oscillator at one end. The other end of the string is fi

Karolina [17]

Answer:

870 N

Explanation:

The expression for velocity of wave in a string is given below

v = $\sqrt{\frac{T}{m} }$ , T is tension and m is mass per unit length .

m = 45 x 10⁻³ / 30 x 10⁻²

= .15 kg/m

Putting the given values in the equation

76 = $\sqrt{\frac{T}{.15} }$

T = 76² x .15

= 866.4

870 N approx.

3 0

3 years ago

You dribble a basketball while walking on a basketball court list and describe 3 pairs of action-reaction forces

elena-s [515]

Answer:

1. Walking

2. Pushing the basketball with hand

3. Ball bouncing off the ground

Explanation:

As per Newton's third law of motion every action has an equal and opposite reaction. Looking at the given scenario following are the pairs of action-reaction forces:

1. Walking: When you walk, you apply action and push the ground and the ground pushes you back with the same force.

2. Pushing the basketball with hand: when you push the ball that is action, the ball also applies force on your hand which is the reaction.

3. Ball bouncing off the ground: When ball hits the ground, it applies force i.e. action and the ground pushes it back with the same force which is the reaction.

5 0

2 years ago

Compute the gravitational force and the electric force between the electron and the proton in the hydrogen atom if they are 5.3

fiasKO [112]

Answer:

Fg = 3.61×10⁻⁴⁷ N.

Fe = 8.2× 10⁻⁸ N.

Fe/Fg = 2.27×10³⁹

Explanation:

From Newton' s law,

Fg = Gm'm/r²...................... Equation 1

Where Fg = gravitational force, m = mass of proton, m' = mass of electron, r = distance between proton and electron, G = Gravitational constant

Given: m = 1.67 x 10⁻²⁷ kg, m' = 9.1×10⁻³¹ kg, r = 5.3×10⁻¹¹ m

Constant: G = 6.67×10⁻¹¹ Nm²/kg²

Substitute into equation 1

Fg = (1.67 x 10⁻²⁷)( 9.1×10⁻³¹ )(6.67×10⁻¹¹)/( 5.3×10⁻¹¹)²

Fg = (101.364×10⁻⁶⁹)/(28.09×10⁻²²)

Fg = 3.61×10⁻⁴⁷ N.

From coulomb's law,

Fe = kqq'/r²................. Equation 2

Where Fe = Electric force, q = charge of proton, q' = charge of electron, r = distance between proton and electron.

Given: q = 1.6×10⁻¹⁹ C, q' = 1.6×10⁻¹⁹ C, r = 5.3×10⁻¹¹ m, k = 9.0×10⁹ Nm²/C².

Substitute into equation 2

Fe = (1.6×10⁻¹⁹)(1.6×10⁻¹⁹)(9.0×10⁹)/(5.3×10⁻¹¹)²

Fe = 23.04×10⁻²⁹/(28.09×10⁻²²)

Fe = 8.2× 10⁻⁸ N.

Therefore,

Fe/Fg = 8.2× 10⁻⁸ /3.61×10⁻⁴⁷

Fe/Fg = 2.27×10³⁹

8 0

3 years ago

Read 2 more answers