Which of these relies on a renewable resource to produce energy

2C3H7OH + 9O2 --> 6CO2 + 8H2O

Ne4ueva [31]

<h3>Answer:</h3>

733 g CO₂

<h3>General Formulas and Concepts:</h3>

Math

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Chemistry

Atomic Structure

Reading a Periodic Table

Stoichiometry

Using Dimensional Analysis

<h3>Explanation:</h3>

Step 1: Define

[RxN - Balanced] 2C₃H₇OH + 9O₂ → 6CO₂ + 8H₂O

[Given] 5.55 mol C₃H₇OH

Step 2: Identify Conversions

[RxN] 2 mol C₃H₇OH → 6 CO₂

Molar Mass of C - 12.01 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of CO₂ - 12.01 + 2(16.00) = 44.01 g/mol

Step 3: Stoichiometry

Set up conversion: $\displaystyle 5.55 \ mol \ C_3H_7OH(\frac{6 \ mol \ CO_2}{2 \ mol \ C_3H_7OH})(\frac{44.01 \ g \ CO_2}{1 \ mol \ CO_2})$
Multiply/Divide: $\displaystyle 732.767 \ g \ CO_2$

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

732.767 g CO₂ ≈ 733 g CO₂

8 0

3 years ago

What volume (in mL) of a 0.200 MHNO3 solution is required to completely react with 27.6 mL of a 0.100 MNa2CO3 solution according

ladessa [460]

Answer:

There is 27.6 mL of a 0.200 M HNO3 solution required

Explanation:

Step 1: The balanced equation is:

Na2CO3(aq)+2HNO3(aq)→2NaNO3(aq)+CO2(g)+H2O(l)

This means for 1 mole Na2CO3 consumed, there is consumed 2 mole of HNO3 and there is produced 2 moles of NaNO3, 1 mole of CO2 and 1 mole of H2O

Step 2: Calculating moles of Na2CO3

moles of Na2CO3 =volume of Na2CO3 * Molarity of Na2CO3

moles of Na2CO3 = 27.6 *10^-3 * 0.1 M = 0.00276 moles

Step 3: Calculating moles of HNO3

In the balanced equation, we can see that for 1 mole of Na2CO3 consumed, there are consumed 2 moles of HNO3.

So for 0.00276 moles consumed of Na2CO3, there are consumed 0.00552 moles of HNO3.

This means 0.00276 moles of the base Na2CO3 would react with 0.00552 moles of the acid HNO3

Step 4: Calculating the volume of HNO3

volume of HNO3 = moles of HNO3 / Molarity of HNO3

volume of HNO3 = 0.00552 moles / 0.200 M = 0.0276 L

0.0276 L = 27.6 ml

There is 27.6 mL of a 0.200 M HNO3 solution required

4 0

3 years ago

What are 4 enzymes responsible for digestion along with their substrate and end product

elena55 [62]

Answer:

4 enzymes responsible for digestion:

1. Salivary amylase ---- substrate: Starch ---- end-product: Maltose

2. Lipase ---- substrate: Lipids (fats and oils) ---- end-product: Fatty acids and glycerol

3. Maltase ---- substrate: Maltose ---- end-product: Glucose

4. Protease ---- substrate: Protein ---- end-product: Amino acids

4 0

3 years ago

What is the most important role that water plays for living organisms?

Flauer [41]

Answer:

A. All organisms need water as energy source

8 0

3 years ago

Read 2 more answers

For which applications would you choose a liquid over a gas or solid?

DedPeter [7]

Answer:

Washing Clothes & Dissolving Sugar

Explanation:

Think about each application:

1) Washing clothes: You kind of need water to do this, or not much washing can be done.

2) Linking brake pedals to the brake pads: You don't need any liquids for this. You need solids.

3) Deodorizing a room: You would problem choose an aerosol, which is sprayed, thus a gas.

4) Carving a sculpture: You would use solid tool and a sold sculpture.

5) Dissolving sugar: You need a liquid to dissolve sugar!

6) Painting a wall: Perhaps, you COULD say that the paint is a liquid... but I'm not sure if that really counts. I believe this application would still be solids.

7) A gear for a machine is a solid!

5 0

3 years ago

Read 2 more answers