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irga5000 [103]
3 years ago
12

Because the block is not moving, the sum of the x components of the forces acting on the block must be zero. Find an expression

for the sum of the x components of the forces acting on the block, using coordinate system b.
Physics
1 answer:
Viktor [21]3 years ago
7 0

Answer:

F_{xtotal} = F_{x} - \mu N

Explanation:

Let the total force be F

The force that produces motion in the x direction is given as, F_{x}

Let the frictional force be given as:

F_{fric} = \mu N

Thus, the net force is given as:

F_{xnet}  = F_{x} - \mu N

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Problem 21-40a:
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Answer:

Part a)

\frac{F_e}{F_g} = 2.74 \times 10^{12}

Part b)

q = 3.37 \times 10^{-4} C

Explanation:

As we know that electric force on electric charge is given as

F = qE

here we have

q = 1.6 \times 10^{-19}C

E = 153 N/C

now force is given as

F = (1.6 \times 10^{-19})(153) = 2.45 \times 10^{-17} N

Gravitational force on electric charge near surface of earth is given as

F_g = mg

F_g = (9.1 \times 10^{-31})(9.81) = 8.93 \times 10^[-30} N

now the ratio of two forces is given as

\frac{F_e}{F_g} = \frac{2.45 \times 10^{-17}}{8.93 \times 10^{-30}}

\frac{F_e}{F_g} = 2.74 \times 10^{12}

Part b)

Now the ball is balanced by the electric force and the force of gravity on it

so here we have

F_g = qE

mg = qE

(5.25 \times 10^{-3})(9.81) = q(153)

here we have

q = 3.37 \times 10^{-4} C

8 0
4 years ago
Imagine you have been asked to create an experimental design to test the hypothesis that talking on a cell phone impairs driving
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A makeshift sign hangs by a wire that is extended over an ideal pulley and is wrapped around a large potted plant on the
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Why is the following situation impossible? Two identical dust particles of mass 1.00 µg are floating in empty space, far from an
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Answer:

This is a conceptual problem so I will try my best to explain the impossible scenario. First of all the two dust particles ara virtually exempt from any external forces and at rest with respect to each other. This could theoretically happen even if it's difficult for that to happen. The problem is that each of the particles have an electric charge which are equal in magnitude and sign. Thus each particle should feel the presence of the other via a force. The forces felt by the particles are equal and opposite facing away from each other so both charges have a net acceleration according to Newton's second law because of the presence of a force in each particle:

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