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mafiozo [28]
3 years ago
7

In 2009, based on concepts similar to those used to estimate U.S. employment figures, the Swedish adult non-institutionalized po

pulation was 7.568 million, the labor force was 4.888 million, and the number of people employed was 4.486 million. According to these numbers, the Swedish labor-force participation rate and unemployment rate were about
Chemistry
1 answer:
ankoles [38]3 years ago
3 0

The answer is 64.6% and 8.2%

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Can someone please help by filling out this table?
tamaranim1 [39]

Answer:

Lithium looses one electron.

The charge - Li^{+} - Cation

Nitrogen gains three electrons - Ni^{3-} - Anion

Boron losses three electron.

The charge - B^{3+} - Cation

Explanation:

Lithium looses one electron.

The charge - Li^{+} - Cation

Nitrogen gains three electrons - Ni^{3-} - Anion

Boron losses three electron.

The charge - B^{3+} - Cation

The complete table is as follows.

5 0
3 years ago
The names of the compounds FeS, NaCl, NaOH, and Pb(CN)2 all end in the suffix
zepelin [54]

Ide is the answer for the test

8 0
4 years ago
A 0.239 gram sample of a gas in a 100-ml flask exerts a pressure of 603 mm Hg at 14 Celsius. What is the gas? (Hint: don’t forge
AlekseyPX

Answer:

A) chlorine

Explanation:

To solve this question we can use:

PV = nRT

In order to solve the moles of the gas. With the moles and the mass we can find the molar mass of the gas to have an idea of its identy:

PV = nRT

PV / RT = n

<em>Where P is pressure: 603mmHg * (1atm / 760mmHg) = 0.7934atm</em>

<em>V = 100mL = 0.100L</em>

<em>R is gas constant = 0.082atmL/molK</em>

<em>T is absolute temperature = 14°C + 273.15 = 287.15K</em>

0.7934atm*0.100L / 0.082atmL/molK*287.15K = n

3.37x10⁻³ moles of the gas

In 0.239g. The molar mass is:

0.239g / 3.37x10⁻³ moles = 70.9g/mol

The gas with this molar mass is Chlorine, Cl₂:

<h3>A) chlorine </h3><h3 />

6 0
3 years ago
WHAT BLOCK IN THE PICTURE HAS:
GREYUIT [131]

Answer:

the highest is "A" and the lower is "C"

7 0
3 years ago
What volume of a 1.0 M HCl is required to completely neutralize 25.0 ml of a 1.0 M KOH?
Karo-lina-s [1.5K]
x 0,025
HCl+KOH--> KCl + H2O
1 1


c=1M
V=25ml=0,025l ( you need the volume to be in l)
c = n/V
n=c*V
n=1*0,025=0,025 m KOH


x=0,025m
c=1 M
V=n/c
V=0,025/1=0,025l=25ml HCl
3 0
3 years ago
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