Answer: An ideal ammeter would have zero resistance, because to ensure that, there is no voltage drop due to the internal resistance. Similarly, an ideal voltmeter would have infinite resistance, because to ensure that there is no current is drawn by the voltmeter.
Explanation: To find the answer, we need to know about the Ammeter and Voltmeter.
<h3>What is an ammeter?</h3>
- An ammeter is a device, that can be used to measure the electric current flows through a circuit in amperes.
- An ideal ammeter would have zero resistance, because to ensure that, there is no voltage drop due to the internal resistance when it is connected in series to measure the current.
<h3>What is voltmeter?</h3>
- A voltmeter is a device, that can be used to measure the electric potential difference generated between the terminals of an electric circuit in volts.
- An ideal voltmeter would have infinite resistance, because to ensure that there is no current is drawn by the voltmeter, when it is connected in parallel to measure the voltage.
Thus, we can conclude that, an ideal ammeter would have zero resistance, because to ensure that, there is no voltage drop due to the internal resistance. Similarly, an ideal voltmeter would have infinite resistance, because to ensure that there is no current is drawn by the voltmeter.
Learn more about the ammeter and voltmeter here:
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Answer:
Who Discovered Gadolinium Gadolinium was only discovered in 1880 by a Swiss chemist called Jean Charles Galissard de Marignac.
Explanation:
When analyzing samples of two minerals which contain small amounts of gadolinium, didymium and gadolinite, he discovered spectroscopic lines that were unrecognisable. Every single element has distinctive spectroscopic lines so he knew he had discovered a new element, and called it gadolinium after Finnish chemist Johan Gadolin.
Answer:
It will take 0.46 seconds to reach home plate by ball.
Explanation:
Answer:
Explanation:
Current in a wire is 120mA
I = 120mA = 120 × 10^-3 A
I = 0.12 A
If the voltage applied at across the wire is tripled
From ohms law
V=IR
R = V / I
Since R is constant
Then,
V / I = K
Then, we can say
V / I = V' / I'
Given that,
Initially
V = V and I = 120mA
Then, V' = 3V and I' =?
So,
V / I = V' / I'
V / 120 = 3V / I'
Cross multiply
V × I' = 120 × 3V
Divide both sides by V
I' = 120 × 3V / V
I' = 360mA
So, the current in the wire when the voltage was tripled is 360mA, the current was also tripled