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3 years ago

How can you make the moon go around in a bigger circle

Physics

2 answers:

zlopas [31]3 years ago

5 0

You would have to give it more mechanical energy.

Like, strap a bunch of powerful rockets to one side of the moon, with all of them pointing in the direction that the moon is already moving in its orbit. Then blast away.

NOTE: There aren't enough rockets or rocket fuel on Earth to make a difference, even if you used ALL of them. The mass of the moon is about

<em>73,476,730,900,000,000,000,000 kilograms</em>

(rounded to the nearest hundred trillion kilograms.)

That's a lot.

Alex_Xolod [135]3 years ago

5 0

I doubt it if you can try

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A hydraulic lift has two connected pistons with cross-sectional areas 15 cm2 and 670 cm2. It is filled with oil of density 510 k

BigorU [14]

Answer:

Explanation:

Given

Cross-sectional area of two areas is

$A_1=15\ cm^2$

$A_2=670\ cm^2$

It is filled with oil of density $\rho _0=510\ kg/m^3$

mass of car place on Large area $M=1100\ kg$

Suppose a mass of m kg is placed on smaller area

According to pascal law's intensity of pressure is same at every point on Liquid

$P_1=P_2$

$\frac{F_1}{A_1}=\frac{F_2}{A_2}$

$\frac{mg}{15}=\frac{Mg}{670}$

$m=1100\times \frac{15}{670}$

$m=24.62\ kg$

4 0

2 years ago

Calculate the pressure on the ground from an 80 kg woman leaning on the back of one of her shoes with a 1cm diameter heel, and c

rodikova [14]

Answer:

Pressure of woman will be $99.87\times 10^5N/m^2$

Pressure of the elephant will be $1716560.50N/m^2$

Explanation:

We have given that mass of the woman m = 80 kg

Acceleration due to gravity $g=9.8m/sec^2$

Diameter of shoes = 1 cm =0.01 m

So radius $r=\frac{d}{2}=\frac{0.01}{2}=0.005m$

So area $A=\pi r^2=3.14\times 0.005^2=7.85\times 10^{-5}m^2$

We know that force is given F = mg

So $F=80\times 9.8=784N$

Now we know that pressure is given by $P=\frac{F}{A}=\frac{784}{7.85\times 10^{-5}}=99.87\times 10^5N/m^2$

Now mass of elephant m = 5500 kg

So force of elephant = 5500×9.8 = 53900 N

Diameter = 20 cm

So radius r = 10 cm

So area will be $A=3.14\times 0.1^2=0.0314m^2$

So pressure will be $P=\frac{53900}{0.0314}=1716560.50N/m^2$

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2 years ago

How do seatbelts reduce injury during a collision ?

RoseWind [281]

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2 years ago

2. Compare the names of the metal elements by themselves to their names what they are part of andows

steposvetlana [31]

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3 years ago

What (in N/C) is the electric field 3.00 m from the center of the terminal of a Van de Graaff with an 8.00 mC charge, noting tha

mixer [17]

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