When the inferior angle of the scapula moves in the superior and lateral direction, the motion is called:
1 answer:
You might be interested in
Answer:
The work done on the canister by the 5.0 N force during this time is
54.06 Joules.
Explanation:
Let the initial kinetic energy of the canister be
KE₁ = =
= 19.44 J in the x direction
Let the the final kinetic energy of the canister be
KE₂ = =
= 73.5 J in the y direction
Therefore from the Newton's first law of motion, the effect of the force is the change of momentum and the difference in energy between the initial and the final
= 73.5 J - 19.44 J = 54.06 J
Answer:
It took Kevin 26 minutes to run from markers 1 to 4
His average speed from mile markers 1 to 4 is 0.154 miles/minute
Kevin must run by average speed 0.1 miles/minute to finish the race
Explanation:
Lets explain how to solve the problem
A half marathon 13.1 miles
Kevin took 8 minutes to run from mile marker 1 to mile marker 2 and
18 minutes to run from mile marker 2 to mile marker 4
→ He took 8 minutes and 18 minutes to run from marker 1 to marker 4
→ The total time of the first 4 marker = 8 + 18 = 26 minutes
<em>It took Kevin 26 minutes to run from markers 1 to 4</em>
<em></em>
Average speed is total distance divided by total time
The average speed of Kevin as he ran from mile marker 1 to mile
marker 4 is the 4 miles divides by 26 minutes
→ Average speed = 4 ÷ 26 = = 0.154 miles/minute
<em>His average speed from mile markers 1 to 4 is 0.154 miles/minute</em>
<em></em>
It took Kevin 71 minutes to pass mile marker 9
Kevin need to complete the race in 112 minutes, then what must
Kevin's average speed be as he travels from mile marker 9 to the
finish line?
The total distance of the race is 13.1 miles, he ran 9 miles
→ The remaining distance = 13.1 - 9 = 4.1 miles
He must run 4.1 miles to complete the race
The total time is 112 minutes, he used 71 minutes to run the first 9 miles
→ The remaining time = 112 - 71 = 41 minutes
He must finish the 4.1 miles in 41 minutes
→ His average speed for the last part of the race = 4.1 ÷ 41 = 0.1 mi/min
<em>Kevin must run by average speed 0.1 miles/minute to finish the race</em>
Answer:
More energy is transferred in situation A
Explanation:
Each of the situations are analyzed as follows;
Situation A
The temperature of the cup of hot chocolate = 40 °C
The temperature of the interior of the freezer in which the chocolate is placed = -20 °C
We note that at 0°C, the water in the chocolate freezes
The energy transferred by the chocolate to the freezer before freezing is given approximately as follows;
E₁ = m×c₁×ΔT₁
Where;
m = The mass of the chocolate
c₁ = The specific heat capacity of water = 4.184 kJ/(kg·K)
ΔT₁ = The change in temperature from 40 °C to 0°C
Therefore, we have;
E₁ = m×4.184×(40 - 0) = 167.360·m kJ
The heat the coffee gives to turn to ice is given as follows;
E₂ = m·
Where;
= The latent heat of fusion = 334 kJ/kg
∴ E₂ = m × 334 kJ/kg = 334·m kJ
The heat required to cool the frozen ice to -20 °C is given as follows;
E₃ = m·c₂·ΔT₂
Where;
c₂ = The specific heat capacity of ice = 2.108 kJ/(kg·K)
Therefore, we have;
E₃ = m × 2.108 ×(0 - (-20)) = 42.16
E₃ = 42.16·m kJ/(kg·K)
The total heat transferred = (167.360 + 334 + 42.16)·m kJ/(kg·K) = 543.52·m kJ/(kg·K)
Situation B
The temperature of the cup of hot chocolate = 90 °C
The temperature of the room in which the chocolate is placed = 25 °C
The heat transferred by the hot cup of coffee, E, is given as follows;
E = m×4.184×(90 - 25) = 271.96
∴ E = 271.96 kJ/(kg·K)
Therefore, the total heat transferred in situation A is approximately twice the heat transferred in situation B and is therefore more than the heat transferred in situation B
Energy transferred in situation A = 543.52 kJ/(kg·K)
Energy transferred in situation B = 271.96 kJ/(kg·K)
Energy transferred in situation A ≈ 2 × Energy transferred in situation B
∴ Energy transferred in situation A > Energy transferred in situation B.