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Mekhanik [1.2K]
2 years ago
13

When the inferior angle of the scapula moves in the superior and lateral direction, the motion is called:

Physics
1 answer:
kkurt [141]2 years ago
8 0

The motion of the inferior angle of the scapula in the superior and lateral direction is called upward rotation.

<h3>What are the possible motions of the scapula?</h3>

The scapula or the shoulder blade has about six different types of motion it undergoes.

The six ways of movement of the scapula are:

  • protraction,
  • retraction,
  • elevation,
  • depression,
  • upward rotation, and
  • downward rotation

When the inferior angle of the scapula moves in the superior and lateral direction, the motion is called upward rotation.

Learn more about scapula motion at: brainly.com/question/16868917

#SPJ12

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Elena-2011 [213]

Answer:

v = 12.86 km/h

v = 3.6 m/s

Explanation:

Given,

The distance, d = 13.5 km

The time, t = 21/20 h

                  =  1.05 h

The velocity of a body is defined as the distance traveled by the time taken.

                                     v = d / t

                                        =  13.5 km / 1.05 h

                                        = 12.86 km/h

The conversion of km/h to m/s

                                   1 km/h = 0.28 m/s

                                     12.86 km/h = 12.86 x 0.28 m/s

                                                         = 3.6 m/s

Hence, the velocity in m/s is, v = 3.6 m/s

7 0
3 years ago
During a test crash an airbag inflates to stop a dummy's forward motion. the dummy's mass is 75kg. If the net force on the dummy
Black_prince [1.1K]
F=ma
a=F/m
=825N/75kg
=825kg*m/75kg*s^2
=11m/s^2 in the direction of the force (ans)
4 0
3 years ago
What did Bohr’s model of the atom include that Rutherford’s model did not have?
hammer [34]
Bohr explained that the electron revolve around a orbit of fixed energy level that Rutherford fails to explain !!!
8 0
3 years ago
Read 2 more answers
An inventor claims to have developed a food freezer that, in steady-state conditions, requires a power input of 0.25 kW to extra
WARRIOR [948]

Answer:

The inventors  claim is not real

a)  No the the freezer cannot operate in such conditions

Explanation:

From the question we are told that

     The  power input is  P_i  = 0.25 kW  =  0.25 *10^{3} \ W

      The  rate of heat transfer J  =  3050 J/s

       The temperature of the freezer content is T = 270 \ K

       The  ambient temperature is  T_a  =  293 \ K

Generally the coefficient of performance of a refrigerator at idea conditions is mathematically represented as

      COP  =  \frac{T }{Ta - T}

substituting values

     COP  =  \frac{270 }{293 - 270}

     COP  =11.7

Generally the coefficient of performance of a refrigerator at real conditions is mathematically represented as

       COP  =  \frac{J}{P_i}

substituting values

       COP  =  \frac{3050}{0.25 *10^{3}}

       COP  = 12.2

Now given that the COP  of an ideal refrigerator is  less that that of a real refrigerator then the claims of the inventor is rejected

This is because the there are loss in the real refrigerator cycle that are suppose to reduce the COP compared to an ideal refrigerator cycle where there no loss that will reduce the COP

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3 years ago
A planet outside of our solar system
Zolol [24]

Answer:

exoplanets is any planet beyond our solar system.

4 0
3 years ago
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