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gogolik [260]
3 years ago
8

What is the theoretical yield of Li3N in grams when 12.8 g of Li is heated with 34.9 g of N2?

Chemistry
1 answer:
Olenka [21]3 years ago
4 0

Answer:- 21.4 grams of Li_3N are formed.

Solution:- The balanced equation is:

6Li+N_2\rightarrow 2Li_3N

From this equation, lithium and nitrogen reacts in 6:1 mol ratio. Limiting reactant gives the theoretical yield of the product. We will calculate the grams of the product for the given grams of both the reactants and see which one of them gives the limited amount of the product. This limited amount of the product will be the theoretical yield.

The molar mass of Li is 6.94 gram per mol and for N_2 It is 28.02 gram per mol. The molar mass of Li_3N is 34.83 gram per mol. The calculations for the grams of the product for given grams of both the reactants are shown below:

12.8gLi(\frac{1molLi}{6.94gLi})(\frac{2molLi_3N}{6molLi})(\frac{34.83gLi_3N}{1molLi_3N})

= 21.4gLi_3N

34.9gN_2(\frac{1molN_2}{28.02gN_2})(\frac{2molLi_3N}{1molN_2})(\frac{34.83gLi_3N}{1molLi_3N})

= 86.8gLi_3N

From above calculations, Li gives least amount of the product. So, 21.4 g of Li_3N are formed.

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