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gogolik [260]
2 years ago
8

What is the theoretical yield of Li3N in grams when 12.8 g of Li is heated with 34.9 g of N2?

Chemistry
1 answer:
Olenka [21]2 years ago
4 0

Answer:- 21.4 grams of Li_3N are formed.

Solution:- The balanced equation is:

6Li+N_2\rightarrow 2Li_3N

From this equation, lithium and nitrogen reacts in 6:1 mol ratio. Limiting reactant gives the theoretical yield of the product. We will calculate the grams of the product for the given grams of both the reactants and see which one of them gives the limited amount of the product. This limited amount of the product will be the theoretical yield.

The molar mass of Li is 6.94 gram per mol and for N_2 It is 28.02 gram per mol. The molar mass of Li_3N is 34.83 gram per mol. The calculations for the grams of the product for given grams of both the reactants are shown below:

12.8gLi(\frac{1molLi}{6.94gLi})(\frac{2molLi_3N}{6molLi})(\frac{34.83gLi_3N}{1molLi_3N})

= 21.4gLi_3N

34.9gN_2(\frac{1molN_2}{28.02gN_2})(\frac{2molLi_3N}{1molN_2})(\frac{34.83gLi_3N}{1molLi_3N})

= 86.8gLi_3N

From above calculations, Li gives least amount of the product. So, 21.4 g of Li_3N are formed.

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The volume of chlorine required is 7.71 L.

The reaction between phosphorus and chlorine is:

2P + 5Cl₂→ 5PCl₅

Therefore, 2  moles of P requires 5 moles of chlorine to react with it.

Given mass of P =3.39 g

Molar mass of P=30.97 g/mol

No. of moles of P = given mass/ molar mass = 3.39 / 30.97 = 0.109 moles

2  moles of P requires 5 moles of chlorine

0.109  moles of P will require 0.109 x 5/2 = 0.2725 moles of chlorine

According to ideal gas equation

PV=nRT

2.04 x V = 0.2725 x 0.0821 x 703

V = 0.2725 x 0.0821 x 703 / 2.04

V = 7.71L

Learn more about ideal gas equation here:

brainly.com/question/3637553

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Lonization Energy decreases as you go down a family (group or column). Explain why this pattern
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Answer:

Explanation:

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3 0
2 years ago
Why do we use scientific notation or scientific exponential numbers in math calculations?
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2. Chromium+oxygen - chromium(III) oxide <br>balanced​
sesenic [268]

Answer:

4Cr + 3O2 —> 2Cr2O3

Explanation:

Information from the question include:

Chromium + oxygen -> chromium(III) oxide

From the word equation given above, the equation can be written as follow:

Cr + O2 —> Cr2O3

The equation can be balance by doing the following:

There are 2 atoms of O on the left side and 3 atoms on the right side. It can be balance by putting 2 in front of Cr2O3 and 3 in front of O2 as shown below:

Cr + 3O2 —> 2Cr2O3

Now, we have 4 atoms of Cr on the right side and 1 atom on the left. It can be balance by putting 4 in front of Cr as shown below:

4Cr + 3O2 —> 2Cr2O3

Now the equation is balanced

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2 years ago
What is the pH of a solution that has a pOH of 5.9
Stella [2.4K]

Answer:

pH = 8.1

Explanation:

Assuming that we are at 25 degrees Celsius, pH + pOH = 14.

We can then plug in the given pOH and solve for pH:

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pH = 14 - 5.9 = 8.1

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