What happens to a glass of sugar solution when sugar is added to it?

The Ka of a certain indicator is 4 ×10−7. The color of HIn is green and that of In− is red. A few drops of the indicator are add

Monica [59]

Answer:

7.4 - 5.4.

Explanation:

The relationship between HIn that is the non-ionized form and the In^-; the ionized form is an equilibrium Reaction which is given below;

HIn(aq) + H2O(l) <--------> H3O^+(aq). + In^-(aq).

From the question, we are given that the ka is 4 ×10^−7, therefore, the mathematical relationship between HIn and In^- is given below;

Ka = [H3O^+] [In^-] / [HIn] = 4 ×10^−7.

The formula we are going to be using to solve this question is given below;

pH = pKa (+ or -) 1.

Recall that the relationship between the ka and pKa;

pKa = - log (ka).

pKa = - log ( 4 ×10^−7).

pKa = 6.4

Therefore, for it to have a distinct color change, the pH range will be;

pH = pKa (+ or -) 1.

pH= 6.4 + 1 = 7.4.

pH= 6.4 - 1 = 5.4.

Hence, the pH range = 7.4 - 5.4.

4 0

3 years ago

Consider the reaction when aqueous solutions of potassium hydroxide and ammonium nitrate are combined. The net ionic equation fo

Reil [10]

Answer: $OH^-(aq)+NH_4^+(aq)\rightarrow NH_3(g)+H_2O(l)$

Explanation:

A double displacement reaction is one in which exchange of ions take place. The salts which are soluble in water are designated by symbol (aq) and those which are insoluble in water and remain in solid form are represented by (s) after their chemical formulas.

$KOH(aq)+NH_4NO_3(aq)\rightarrow KNO_3(aq)+NH_3(g)+H_2O(l)$

The equation can be written in terms of ions as:

$K^+(aq)+OH^-(aq)+NH_4^+(aq)+NO_3^-(aq)\rightarrow K^+(aq)+NO_3^-(aq)+NH_3(g)+H_2O(l)$

Spectator ions are defined as the ions which does not get involved in a chemical equation or they are ions which are found on both the sides of the chemical reaction present in ionic form.

The ions which are present on both the sides of the equation are potassium and nitrate ions and hence are not involved in net ionic equation.

Hence, the net ionic equation is :

$OH^-(aq)+NH_4^+(aq)\rightarrow NH_3(g)+H_2O(l)$

6 0

4 years ago

Electrons are charged particles. Moving charged particles are a current. There is a current of electrons flowing through a coppe

Naddik [55]

Answer:

As the electrons flow through the wire, <em>electric current </em>is generated around the wire.

Explanation:

The rate of flow of charged particles in a given time is termed as the flow of current. Mostly the charge carriers are termed as electrons in a conductor. So the flow of electrons or movement of charged particles in a given time is the generation of electric current in that current. As the ratio of charge to time at which the charge is moving from one point to another is termed as the current flow in that time.

$Current=\frac{Charge}{Time}$

Thus, in the present case of electrons flowing in that wire will lead to generating of electric current in the opposite direction around the wire.

6 0

4 years ago

Read 2 more answers

For some disorders, any child, male or female, would have to inherit two copies of the affected gene.

saw5 [17]

Answer:

i think its cystic fibrosis

Explanation:

im so sorry if this is wrong

4 0

3 years ago

How is earths moon different from the moons of other planets