The reaction formula of this is NaCl + AgNO3 = NaNO3 + AgCl. The mole number of NaCl is 4/58.5=0.068 mol. The mole number of AgNO3 is 10/170=0.059 mol. So the NaCl is excess.
Two [hydrogen] atoms and one [oxygen] atom
Answer:
5.6 × 10^4
this is ur answer hope it helps u
