In france grapes are 1.83 euros per kilogram. What is the cost of grapes in dollars per pound if the exchange rate is 1.40 dollars per euro
1.83 euros x 1.40 = 2.56 dollars
1 pound = 0.454 kilogram
1.83 euros per kilogram = 2.56 x 0.454 = 1.16 dollars per pound
Given:
M = 0.0150 mol/L HF solution
T = 26°C = 299.15 K
π = 0.449 atm
Required:
percent ionization
Solution:
First, we get the van't Hoff factor using this equation:
π = i MRT
0.449 atm = i (0.0150 mol/L) (0.08206 L atm / mol K) (299.15 K)
i = 1.219367
Next, calculate the concentration of the ions and the acid.
We let x = [H+] = [F-]
[HF] = 0.0150 - x
Adding all the concentration and equating to iM
x +x + 0.0150 - x = <span>1.219367 (0.0150)
x = 3.2905 x 10^-3
percent dissociation = (x/M) (100) = (3.2905 x 10-3/0.0150) (100) = 21.94%
Also,
percent dissociation = (i -1) (100) = (</span><span>1.219367 * 1) (100) = 21.94%</span>
Answer:
they tend to be base
Explanation:
this because when they are manufactured they dont tend to use acid solution
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