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3 years ago

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HCl reacts with Barium Hydroxide to produce barium chloride and water. how many ml of a 3.00 M hydrochloric acid solution would

be required to react with 25.5 ml of a 4.65 M barium hydroxide solution?

1 answer:

ollegr [7]3 years ago

3 0

THINK OF GUMMY BEARS IN A TEST TUBE AND IN THAT TEST TUBE THEIRS A SUBSTANCE ACID IT EX PLODS LOOK IT UP ON YOU TUBE

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select from this list the one metal or alloy that is best suited for each of the following applications, and cite at least one r

Brut [27]

<em>List of metal or alloy that is best-suited include :</em>

<em>1) Block of an </em><em>internal combustion </em><em>engine is made of grey cast </em><em>iron </em><em>because it is </em><em>ductile </em><em>and hard enough to bear the loads.</em>

<em>2) Steam heat exchanger is made up of </em><em>stainless steel </em><em>material as it has high resistance to </em><em>corrosion </em><em>and has the capacity to bear high-</em><em>temperature </em><em>differences.</em>

<em>3) For jet engine </em><em>turbofan blades</em><em>, titanium alloys are being used because they can able to bear high pressure and high energy loads.</em>

<em>4) Tool </em><em>steel </em><em>is used to make drill bit material as it has high </em><em>tensile </em><em>and point strength.</em>

<em>5) </em><em>Aluminum alloys </em><em>are used for </em><em>cryogenic </em><em>applications as it is the best suited for work at low </em><em>temperatures</em><em>.</em>

<em>6) </em><em>Magnesium </em><em>is used for </em><em>pyrotechnics </em><em>as it gives works on the effect of heat, </em><em>light</em><em>, and gas. </em>

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Alloy, a metallic substance composed of two or more elements, as both a compound or a solution. The components of alloys are ordinarily themselves metals, though carbon, a nonmetal, is an essential constituent of metal.

Alloys, in trendy, are more potent and harder, less malleable, much less ductile, and greater corrosion-resistant than the alloy's predominant metallic.

An alloy is created with the aid of mixing metallic with another issue, both any other metal or a nonmetal substance. Metallic alloys are commonly made by means of melting the substances, mixing them collectively, after which letting them cool to room temperature, ensuing in a strong material.

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Learn more about Alloy here:-brainly.com/question/1759694

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3 0

1 year ago

Can someone tell me how to draw a atomic model for Cd

tensa zangetsu [6.8K]

Explanation:

there you go you can just look up atomic model for CD and click images

5 0

2 years ago

Identify the two main materials that can be found in the inner and outer core layers of the earth.

Mrrafil [7]

A. Iron D. Nickel hope this helps you!

6 0

2 years ago

cylinder contains 250 g of Helium at 200 K. The external pressure is constant at 1 atm. The temperature of the surroundings is l

brilliants [131]

Answer:

The system gains 126100 J

Explanation:

The heat can be calculated by the equation:

Q = nxCxΔT, where Q is the heat, C is the heat capacity,n is the number of moles and ΔT is the variation of temperature (final - initial). The number of moles is the mass divided by the molar mass, so:

n = 250/4 = 62.5 mol.

The system must be in thermal equilibrium with the surroundings, so if the temperature of the surroundings decreased 97 K, the temperature of the system increased by 97 K, so ΔT = 97 K

Q = 62.5x20.8x97

Q = 126100 J

6 0

3 years ago

How many moles, kmols in: 100 g of CO2, 1 litre of ethyl alcohol of density 0.789 g/cm3 and a) 1.5m3 of O2 at 25°C and 1 atm. b)

Nutka1998 [239]

Explanation:

1) Mass of carbon dioxide = 100 g

Molar mass of carbon dioxide = 44 g/mol

Moles of carbon dioxide = $\frac{100 g}{44 g/mol}=2.273 moles$

1 mol = 0.001 kmol

2.273 moles= 2.273 × 0.001 kmol = $2.273\times 10^{-3} kmol$

2) 1 liter of ethyl alcohol of density $0.789 g/cm^3$

Volume of ethyl alcohol ,V= 1 L = 1000 mL

Density of ethyl alcohol =d = $0.789 g/cm^3$

$1 cm^3=1 mL$

Mass of ethyl alcohol = m

$m=d\times V=0.789 g/cm^3\times 1000 mL=789 g$

Molar mass of ethyl alcohol = 46 g/mol

Moles of ethyl alcohol = $\frac{789 g}{46 g/mol}=17.152 mol$

$17.152 mol=17.152\times 0.001 kmol=1.7152\times 10^{-4} kmol$

3) Volume of oxygen gas,V = $1.5 m^3=1500 L$

$1 m^3= 1000 L$

Temperature of the gas = T= 25°C = 298.15 K

Pressure of the gas ,P= 1 atm

Moles of oxygen gas = n

$PV=nRT$

$n=\frac{RT}{PV}=\frac{0.0821 atm L/mol K\times 298.15 K}{1 atm\times 1500 L}=0.01632 mol$

0.01632 mol = 0.01632 × 0.001 kmol= $1.632\times 10^{-5} kmol$

4) Volume water in mixture = 1 L

Density of water = $1000 kg/m^3=\frac{1,000,000 g}{1000 L}=1000 g/L$

Mass of water = $1000 g/L\times 1 L = 1000 g$

Volume of alcohol = 2.5 L

Density of alcohol = $789 kg/m^3=\frac{789000 g}{1000 L}=789 g/L$

Mass of alcohol = $789 g/L\times 2.5 L = 1972.5 g$

Mass of mixture = 1000 g + 1972.5 g = 2972.5 g

Mass percentage of water :

$\frac{1000 g}{2972.5 g}\times 100=33.64\%$

Mass percentage of alcohol :

$\frac{1972.5 g}{2972.5 g}\times 100=66.36\%$

Moles of water :

$n_1=\frac{1000 g}{18 g/mol}=55.55 mol$

Moles of alcohol =

$n_2=\frac{1972.5 g}{46 g/mol}=42.88 mol$

Mole fraction of water :

$\chi_1=\frac{n_1}{n_1+n_2}=\frac{55.55 mol}{55.55 mol+42.88 mol}=0.5644$

Mole fraction of alcohol :

$\chi_2=\frac{n_2}{n_1+n_2}=\frac{42.88 mol}{55.55 mol+42.88 mol}=0.4356$

3 0

2 years ago