A region R is enclosed by the coordinate axes and the graph of y=k(x-5)^2, k>0. When this region is revolved around the x-axi

Question

Komok [63]

2 years ago

12

A region R is enclosed by the coordinate axes and the graph of y=k(x-5)^2, k>0. When this region is revolved around the x-axi

s, the solid formed has a volume of 2500pi cubic units.
What is the value of k?

Mathematics

1 answer:

irinina [24] · Answer 1 · 2022-06-24T21:06:43+03:00

The question is asking to calculate the value of K if the R is enclosed be the coordinate axis and the graph of y = k(x-5)^2, and K>0. Base on that, the value of K would be K is equals to 2, I hope you are satisfied with my answer and feel free to ask for more if you have questions and further clarifications