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3 years ago

What effects a materials resistance

Physics

1 answer:

goblinko [34]3 years ago

8 0

Answer:

The type of material of which the resistor is made.

The length of the resistor.

The thickness of the resistor.

The temperature of the conductor.

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An astronaut holds a rock 100m above the surface of Planet X . The rock is then thrown upward with a speed of 15m/s , as shown i

Butoxors [25]

Answer: $5 m/s^{2}$

Explanation:

The described situation is is related to vertical motion (and free fall). So, we can use the following equation that models what happens with this rock:

$y=y_{o}+V_{o}sin\theta t-\frac{1}{2}gt^{2}$ (1)

Where:

$y=0m$ is the rock's final height

$y_{o}=100 m$ is the rock's initial height

$V_{o}=15 m/s$ is the rock's initial velocity

$\theta=90\°$ is the angle at which the rock was thrown (directly upwards)

$t=10 s$ is the time

$g$ is the acceleration due gravity in Planet X

Then, isolating $g$ and taking into account $sin(90\°)=1$ :

$g=(-\frac{2}{t^{2}})(y-y_{o}-V_{o}t)$ (2)

$g=(-\frac{2}{(10 s)^{2}})(0 m-100 m-(15 m/s)(10 s))$ (3)

Finally:

$g=5 m/s^{2}$ (4) This is the acceleration due gravity in Planet X

7 0

3 years ago

3. What is the potential energy of a 8 Newton book sitting on a shelf that is 12 meters high?

Svetradugi [14.3K]

Answer:

P = 96 J

Explanation:

Given that,

Weight of the book, W = mg = 8 N

It is placed at a height of 12 m

We need to find the potential energy of the book. The potential energy of an object is given by the formula as follows :

E = mgh

mg = Weight

$E=8\ N\times 12\ m\\E=96\ J$

So, the potential energy of the book is 96 J.

8 0

4 years ago

Suppose a skydiver (mass=75kg) is falling toward the earth when the skydiver is 100m above the earth he is moving at 60m/s at th

IRISSAK [1]

Given:

Mass(m)=75kg

Height (h) =100m

v(velocity)=60m/s

a(g)=9.8m/s^2(since it is a free falling object)

Now we know that

v=u+at

We know that

Potential energy=mgh

Where m is the mass

g is the acceleration due to gravity

h is the height above the ground

Substituting the above values we get

Potential energy=75 x 9.8 x 100

=73500N

Now kinetic energy =1/2mv^2

Where m is the mass

v is the velocity

Kinetic energy= 1/2 (75x60 x 60)

Kinetic energy=135000N

Now mechanical energy=

Kinetic energy+ Potential energy

Substituting the values in the above formula we get

Mechanical energy= 73500+135000

=208500N

7 0

3 years ago

Read 2 more answers

A conducting loop of radius 1.50 cm and resistance 8 × 10−6Ω is perpendicular to a uniform magnetic field of magnitude 23.0 × 10

Anika [276]

To solve this problem it is necessary to apply the concepts related to electromotive force or induced voltage.

By definition we know that the induced emf in the loop is equal to the negative of the change in the magnetic field, that is,

$\epsilon = -A \times \frac{\Delta B}{\Delta t}$

$\epsilon = -A \times (\frac{B_f-B_i}{t_f-t_i})$

Where A is the area of the loop, B the magnetic field and t the time.

Replacing with our values we have that

$\epsilon = -(\pi (1.5*10^{-2})^2)(\frac{0-23*10^{-6}}{7*10^{-3}-0})$

$\epsilon = 2.3225*10^{-6}V$

Therefore the thermal energy produced is given by

$E = P*t = \frac{\epsilon^2}{R}t$

$E = \frac{(2.3225*10^{-6})^2}{8*10^{-6}}*(7*10^{-3})$

$E = 4.719*10^{-9}J$

The thermal energy produced in the loop is $4.719*10^{-9}J$

4 0

3 years ago

When a car of mass 1200 kg, going with speed 30 m/s, rounds an unbanked curve of radius 150 m, what is the minimum coefficient o

Nana76 [90]

Answer:

$\mu_s=0.61$

Explanation:

In order for the car does not slip, the frictional force must be equal to the centripetal force due to the circular motion. According to the free body diagram:

$\sum F_y:N=mg\\\sum F_x:F_f=F_c$

The frictional force is given by:

$F_f=\mu_s N=\mu_s mg$

The centripetal force is defined as:

$F_c=ma_c=m\frac{v^2}{r}$

Here v is the linear speed and r is the radius of the circular motion. Replacing this equations:

$\mu_smg=m\frac{v^2}{r}\\\mu_s=\frac{v^2}{gr}\\\mu_s=\frac{(30\frac{m}{s})^2}{(9.8\frac{m}{s^2})(150m)}\\\mu_s=0.61$

8 0

4 years ago