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IceJOKER [234]
3 years ago
11

A 35,000 Newton car runs up a hill that is 45.5 meters high in 1.6 seconds. what power did it exert?

Chemistry
1 answer:
Evgesh-ka [11]3 years ago
7 0

Answer:

995.313KW

Explanation:

the explanation is in the picture

please like and Mark as brainliest

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(01.01 MC)
lys-0071 [83]

The answer would be option B "I believe there is life on other planets." Scientific statements have a possibility to be wrong. It's not option A because option A is a opinion. It's not option C because option C is a fact. It's not option D because option D is a opinion.

Hope this helps!

8 0
3 years ago
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What is milk best described as? solution, suspension, compound, or colloid?
Debora [2.8K]
Milk is a complex colloidal system.
7 0
3 years ago
Calculate the Ka for the following acid. Determine if it is a strong or weak acid.
vladimir1956 [14]

Answer:

a) Ka= 7.1 × 10⁻⁴; This is a weak acid because the acid is not completely dissociated in solution.

Explanation:

Step 1: Write the dissociation reaction for nitrous acid

HNO₂(aq) ⇄ H⁺(aq) and NO₂⁻(aq)

Step 2: Calculate the acid dissociation constant

Ka = [H⁺] × [NO₂⁻] / [HNO₂]

Ka = 0.022 × 0.022 / 0.68

Ka = 7.1 × 10⁻⁴

Step 3: Determine the strength of the acid

Since Ka is very small, nitrous acid is a weak acid, not completely dissociated in solution.

4 0
3 years ago
What is the missing number in the sequence 3,5,9,_,15,23,33
balu736 [363]

Answer:

In every sequence even numbers are added in order.

3, 5, 9, 15, 23, 33

6 0
3 years ago
Read 2 more answers
How much energy is required to raise the temperature of 3 kg of iron from 20° C to 25°C? Use the table below and this equation:
ElenaW [278]

The energy required to raise the temperature of 3 kg of iron from 20° C to 25°C is 6,750 J( Option B)

<u>Explanation:</u>

Given:

Specific Heat capacity of Iron= 0.450 J/ g °C

To Find:

Required Energy to raise the Temperature

Formula:

Amount of energy required is given by the formula,

Q = mC (ΔT)

Solution:

M = mass of the iron in g

So 3 kg = 3000 g

C = specific heat of iron = 0.450 J/ g °C [ from the given table]

ΔT = change in temperature = 25° C - 20°C = 5°C

Plugin the values, we will get,

Q = 3000 g ×  0.450 J/ g °C ×  5°C

 = 6,750 J

So the energy required is 6,750 J.

7 0
3 years ago
Read 2 more answers
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