1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
dusya [7]
3 years ago
8

Decide whether you agree or disagree with the statement, "New theories in science are

Chemistry
1 answer:
Brrunno [24]3 years ago
3 0

Answer:

Time is relative - and science is still arguing about singlet versus doublet Carbenes; they fought over whether Oxygen was “real”, and refused to believe in Radium until one by one they SAW that drop glow! (And affect photographic film).

Explatnation:

You might be interested in
A solution that has a relatively large amount of dissolved solute is called a(n) _______________________ solution.
OleMash [197]
Ionic is the correct answer please let us know what you think
7 0
4 years ago
Read 2 more answers
Taken all together the reactions of the human body are
jasenka [17]
The reactions of the human body are exothermic
8 0
3 years ago
A rigid tank contains 0.66 mol of oxygen (O2). Find the mass of oxygen that must be withdrawn from the tank to lower the pressur
dsp73

Answer:

12.8 g of O_{2} must be withdrawn from tank

Explanation:

Let's assume O_{2} gas inside tank behaves ideally.

According to ideal gas equation- PV=nRT

where P is pressure of O_{2}, V is volume of O_{2}, n is number of moles of O_{2}, R is gas constant and T is temperature in kelvin scale.

We can also write, \frac{V}{RT}=\frac{n}{P}

Here V, T and R are constants.

So, \frac{n}{P} ratio will also be constant before and after removal of O_{2} from tank

Hence, \frac{n_{before}}{P_{before}}=\frac{n_{after}}{P_{after}}

Here, \frac{n_{before}}{P_{before}}=\frac{0.66mol}{43atm} and P_{after}=17atm

So, n_{after}=\frac{n_{before}}{P_{before}}\times P_{after}=\frac{0.66mol}{43atm}\times 17atm=0.26mol

So, moles of O_{2} must be withdrawn = (0.66 - 0.26) mol = 0.40 mol

Molar mass of O_{2} = 32 g/mol

So, mass of O_{2} must be withdrawn = (32\times 0.40)g=12.8g

7 0
3 years ago
What is the molarity of a solution prepared by dissolving 10.7 g NaI in 0.250 L?0.0714
hjlf

Answer:0.286M

Explanation:

10.7g / 149.89g/mol×0.25L

4 0
3 years ago
Read 2 more answers
The molecule CH20 contains two single bonds and one double bond.<br> True<br> False
dem82 [27]

Answer:

True

Explanation:

The molecule CH20 contains two single bonds and one double bond.

6 0
3 years ago
Other questions:
  • Which of these is an acid?
    6·2 answers
  • A gas at 80 kPa occupies a volume of 5 mL. What volume will the gas occupy at 70 kPa
    12·1 answer
  • You have a gas at 453 mm Hg with a volume of 700 mL and a temperature of 25 °C, what will the temperature of the gas be, if you
    5·1 answer
  • Any entrée can be labeled "healthy" on a menu as long as it contains natural ingredients. True False
    15·2 answers
  • Give one example of frequency which an elephant can hear but which a tiger cannot hear include a unit in ansawer
    5·1 answer
  • Sulfuric acid is essential to dozens of important industries from steelmaking to plastics and pharmaceuticals. More sulfuric aci
    10·1 answer
  • Three reasons why friction is needed
    15·1 answer
  • Which state of matter has the highest energy? *
    5·1 answer
  • Match each definition to the appropriate term.
    9·1 answer
  • What is true regarding the calculation in redox titration? group of answer choices moles of the oxidant equal mole of the reduct
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!