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Ratling [72]
4 years ago
7

A tool whose coefficient of kinetic friction with the wheel is 0.60 is pressed perpendicularly against the wheel with a force of

40.0 N. What torque must be supplied by the motor to keep the wheel rotating at a constant angular velocity?
Physics
1 answer:
LenaWriter [7]4 years ago
6 0

Answer:

The torque must be supplied by the motor to keep the wheel rotating at a constant angular velocity is 12 N-m.

Explanation:

Given that,

The  coefficient of kinetic friction with the wheel is 0.60

Force acting against the wheel, F = 40 N

Let the distance is, r = 0.5 m

Torque is given by the product of force and distance. Here, the force will be :

F=\mu F\\\\F=0.6\times 40\\\\F=24\ N

Torque is given by :

\tau=F\times r\\\\\tau=24\times 0.5\\\\\tau=12\ N-m

So, the torque must be supplied by the motor to keep the wheel rotating at a constant angular velocity is 12 N-m.

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A billiard ball with a mass of 1.5kg is moving at 25m/s and strikes a second ball with a mass of 2.3 kg that is motionless. Find
aliya0001 [1]

Answer:

The velocity of the second ball after the collision will be 16.3 m/s.

Step-by-Step Explanation:

Law of conservation of momentum states that the total momentum of an isolated remains the same before and after the collision.

Let: mass of the first ball = m1 = 1.5 kg

mass of the second ball = m2 =  2.3 kg

Momentum before the collision:

velocity of the first ball = v1 = 25 m/s

velocity of the second ball = v2 = 0 m/s

[tex] Initial momentum = m1v1 + m2v2 = 1.5*25 + 2.3*0 = 37.5 kgm/s [\tex]

Momentum after the collision:

velocity of the first ball = v1 = 0 m/s

velocity of the second ball = v2 = x

[tex]momentum after the collision= m1v1 + m2v2 = 1.5*0 + 2.3*x = 2.3*x[\tex]

According to law of conservation of momentum:

Initial momentum = Momentum after collision

37.5 = 2.3*x

⇒ x = 37.5/2.3

x = 16.3 m/s

4 0
3 years ago
PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!! I CANNOT RETAKE THIS!!
Tasya [4]

Answer:

98 N

Explanation:

The weight of an object is given by:

W=mg

where

m is the mass of the object

g=9.8 m/s^2 is the acceleration due to gravity

In this problem, the mass of the lemur is m=10 kg, so its weight is

W=mg=(10 kg)(9.8 m/s^2)=98 N

3 0
3 years ago
A beam oflight is reflected off a mirror. If the angle of incidence is 30 degrees, according to the Law of Reflection the angle
zaharov [31]

Answer:

30°

Explanation:

According to the second law of reflection, it States that the angle of incidence i is equal to the angle of reflection r.

The angle of incidence is known to be the angle between the incident ray and the normal.

The Angle of reflection is the angle between the reflected ray and the normal.

This normal ray is a ray that is perpendicular to the surface.

According to the question, if the beam of light is reflected off the surface and its angle of incidence is 30°, its angle of reflection will also be 30° i.e i=r = 30°

7 0
4 years ago
When electrons are shared, the type of bonding is called _____.
lutik1710 [3]
It's called covelant bonding
5 0
3 years ago
The tires of a car make 77 revolutions as the car reduces its speed uniformly from 95.0 km/h to 65.0 km/h. The tires have a diam
nika2105 [10]

Answer:

Explanation:

95.0 km/hr = 26.39 m/s

65 km/hr = 18.06 m/s

Circumference of a tire is 0.9π m

77 revolutions is a distance of

77(0.9π) = 69.3π m

v² = u² + 2as

a = (v² - u²) / 2s

a = (18.06² - 26.39²) / (2(69.3π))

a = -0.85 m/s²

s = (v² - u²) / 2a

s = (0² - 26.39²) / 2(-0.85)

s = 409 m

5 0
3 years ago
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