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Oksi-84 [34.3K]
3 years ago
5

When does a star reach equilibrium?

Physics
1 answer:
LenaWriter [7]3 years ago
6 0
A protostar reaches equilibrium when gravity is balanced by the outward force of nuclear fusion. 
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Un Esquiador Inicia un Salto Horizontal con una velocidad Inicial de 25 m/s. La Altura al Final de la Rampa es de 80 m del punto
Evgesh-ka [11]

Responder:

Explicación:

Para que podamos calcular el tiempo que le tomará al esquiador permanecer en el aire, encontraremos el tiempo de vuelo como se muestra;

T = 2Usin theta / 2

theta = 90 grados

U = 25 m / s

T = 25sin90 / 2 (9,8)

T = 25 / 19,62

T = 1,27 segundos

Por lo tanto, los cielos usarán 1.27 segundos en el aire.

La distancia horizontal es el rango;

Rango R = U√2H / g

R = 25√2 (80) /9,8

R = 25√160 / 9,8

R = 25 * √16,326

R = 25 * 4.04

R = 101,02 m

Por tanto, la distancia horizontal recorrida por el esquiador es 101,02 m

5 0
3 years ago
Two resistors, R1 and R2, are connected
marusya05 [52]

Answer:

18 ohms

Explanation:

V = I(R1 + R2)

5V = (0.167A)(12 ohms + R2)

Solving for R2

R2 = 18 ohms

3 0
3 years ago
Which best explains why making a pancake from batter is an example of a chemical change?
kenny6666 [7]

Answer:

A. the pancake that forms is a different state of matter.

Explanation:

because the pancake mix is liquid ,and when you cook it you for a solid.

8 0
3 years ago
Read 2 more answers
Consider as a system the Sun with Saturn in a circular orbit around it. Find the magnitude of the change in the velocity of the
Doss [256]

Answer:

v_{su} = 19.44 m/s

Explanation:

m_{su}=5.68x10^{29}kg\\m_{sa}=5.68x10^{26}kg

T=9.29x10^8\\r_{o}=1.43x10^{12}

If the sun considered as x=0 on the axis to put the center of the mass as a:

m_{su}*r_{o}=(m_{sa}+m_{su})*r_{1}

solve to r1

r_1=\frac{m_{sa}*r_{o}}{m_{sa}+m_{su}}=\frac{5.68x10^{26}*1.43x10^{12}}{5.68x10^{26}+5.68x10^{26}}

r_1=1.428x10^9m

Now convert to coordinates centered on the center of mass.  call the new coordinates x' and y' (we won't need y').  Now since in the sun centered coordinates the angular momentum was  

L = \frac{m_{sa}*2*pi*r_1^2}{T}

where T = orbital period

then L'(x',y') = L(x) by conservation of angular momentum.  So that means

L_{sun}=\frac{m_{sa}*2*\pi *( 2r_{o}*r_1 -r_1^2)}{T}

Since

L_{su}= m_{su}*v_{su}*r_1

then

v_{su}=\frac{m_{sa}*2*pi*(2r_{o}*r_{1}-r_{1}^2)}{T*m_{sa}*r_1}

v_{su} = 19.44 m/s

7 0
3 years ago
Under state law, what is the blood-alcohol limit for legally operating a motor vehicle?
Ymorist [56]

Answer:

HOPE IT HELPS....

Explanation:

CORRECT ANSWER IS 0.08

THANK YOU,

PLZ MARK ME AS BRAINLIST

5 0
3 years ago
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