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Aleksandr-060686 [28]
3 years ago
5

Problem #3: 3.6. A diode has wdo = 0.4 µm and φj = 0.85 V. (a) What reverse bias is required to triple the depletion-layer width

? (b) What is the depletion region width if a reverse bias of 7 V is applied to the diode?

Physics
1 answer:
Alchen [17]3 years ago
7 0

Answer:

a) 6.8 Volt

b) 1.21Цm

Explanation:

We are given from the question that

   The zero -bias depletion layer width(W_{do}) is 0.4Цm

  The built in voltage φj  is 0.85V

Now to calculate the reverse voltage( V_{R}) that would be required  to triple the depletion - layer width.

  The depletion - layer width (W_{d}) of the diode has the formula

                          W_{d} = W_{do} \sqrt{1 + \frac{V_{R} }{Qj} }

    For three times of   W_{d} we have

        3W_{d} = W_{do} \sqrt{1 +\frac{V_{R} }{Qj} }

         =>      \frac{V_{R} }{Qj} = 3^{2} -1

        => V_{R} = 8Qj

        Substituting value of φj

       We have

                         V_{R} = 8(0.85V)

                               =   6.8 V

The required bias voltage  V_{R} is  6.8 V

   The solution for the b part of the question is uploaded on first image

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