Answer:
1.37 x 
CFU/mL
Explanation:
First, the dilution factor needs to be calculated.
Since four 9 ml dilution blanks were prepared, the dilution factor that yielded 137 colonies is of 
.
Next is to divide the colony forming unit from the dilution by the dilution factor:
137/ = 137 x 
In order to get the CFU/ml, divide the CFU from the dilution by the plated volume (1 mL) from the final dilution tube.
137 x /1 = 1.37 x
Hence, the CFU/ml present in the original <em>E. coli </em> sample is 1.37 x .
cfu/ml = (no. of colonies x dilution factor) / volume of culture plate
Answer: I believe it is A.
Explanation:
Answer:
hahahaa i can get the points
Explanation:
yes it is again LOL thanks
Rules for naming ionic compounds with transition metal requires the elementary name of metal followed the anion name with suffix ide.
<h3>What are ionic compounds?</h3>
Ionic compounds are made up of ions, which are charged particles that occur when an atom (or group of atoms) acquires or loses electrons. Generally cations are metals and anions are non metals in it.
Following rules will be considered during naming:
- First determine the metal's elemental name.
- Give the nonmetal its elemental name and the suffix -ide.
- Use roman numerals to denote positive charge when naming metals that can have distinct oxidation states.
- Name the polyatomic ions according to their names.
Hence rules for naming are listed above.
To know more about nomenclature of ionic compounds, visit the below link:
brainly.com/question/18672152
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