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Nadya [2.5K]
3 years ago
5

1. Initial velocity 5m/s, final velocity 36km/hr, acceleration 1.25m/s/s. Distance?

Physics
2 answers:
bazaltina [42]3 years ago
7 0

Answer:

1.25ml

Explanation:

multioply

Ipatiy [6.2K]3 years ago
5 0

Answer:

31.25m

Explanation:

Check attachment  

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The player that possess the best ball handling skills and usually handles

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Read more on brainly.com/question/25759951

4 0
2 years ago
If 1495 j of heat is needed to raise the temperature of a 351 g sample of a metal from 55.0°c to 66.0°c, what is the specific he
forsale [732]
The amount of heat needed to increase the temperature of a substance by \Delta T is given by
Q= mC_s \Delta T
where m is the mass of the substance, Cs is its specific heat capacity and \Delta T is the increase of temperature.

If we re-arrange the formula, we get
C_s =  \frac{Q}{m \Delta T}
And if we plug the data of the problem into the equation, we can find the specific heat capacity of the substance:
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6 0
3 years ago
Read 2 more answers
How long does it take a man to travel 6 km if his speed is 3km/h?
Ymorist [56]

why did my answer get deleted??

oh yeah i put a link on there- oopsies.

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I got 30!

3 0
2 years ago
work done as mass 1 moves to mass 2. the gravitational force between two point masses separated by a distance r is proportional
pav-90 [236]

Answer:

gravitational force

3 0
3 years ago
Ali mixes 20g of Sodium Chloride in 100g of water at 15 Degree °C. Calculate the mass of the solution
Lera25 [3.4K]

Answer:

The mass of the solution is 120 g.

Explanation:

The mass of the solution is given by:

m_{sol} = m_{1} + m_{2}

Where:

m_{sol}: is the mass of the solution

m_{1}: is the mass of the solvent

m_{2}: is the mass of the solute

In the solution, the solvent is the majority compound (in mass) and the solute is the minority (in mass), so the solvent is the water and the solute is sodium chloride.          

Hence, the mass of the solution is:

m_{sol} = m_{1} + m_{2} = 100 g + 20 g = 120 g  

I hope it helps you!                  

7 0
2 years ago
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