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Kay [80]
3 years ago
5

Properties can be observed only when the substance in a sample of matter are changing into different substance

Physics
1 answer:
Zolol [24]3 years ago
8 0

The complete statement is "chemical properties can be observed only when the substance in a sample of matter are changing into different substance".


It states a key concept in chemistry.


A chemical property is the ability of a substance, element or compound, to <em>transform</em> into other substances either <em>by decomposing or by combining</em> with one or more substances.


This transformation is defined as chemical reaction.


During chemical reactions some chemical bonds  are broken and others are formed leading to the formation of one or more different substances called products.


Some examples of chemical properties are: reactivity with oxygen, reactivity with water, acidity, basicity, oxidation, reduction. The only way to tell if a substance has certain chemical property is by letting it react and so observe the change of the original substance into one or more different substances.

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How long would it take a 4,560 watt motor to raise a 166 kg piano to an apartment window
IrinaK [193]

Answer:

Explanation:

We need the power equation here:

P = W/t where W is work and is defined as

W = F*displacement.

Force is a measure in Newtons, which is also weight. We have the mass of the piano, but we need to find the weight:

w = mg so

w = 166(9.8) so

w = 1600N, rounded to the correct number of sig dig. We use that now in the power equation:

4560=\frac{(1600)(15)}{t} and isolating the unknown:

t=\frac{(1600)(15)}{4560} so

t = 5.3 seconds

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Which of the following is the most dense?
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The angular momentum of a flywheel having a rotational inertia of 0.140 kg ·m2 about its central axis decreases from 3.00 to 0.8
Rasek [7]

Answer

given,

I = 0.140 kg ·m²

decrease from 3.00 to 0.800 kg ·m²/s in 1.50 s.

a) \tau = \dfrac{\Delta L}{\Delta t}

   \tau = \dfrac{0.8-3}{1.5}

        τ = -1.467 N m

b) angle at which fly wheel will turn

   \theta= \omega t +\dfrac{1}{2}\alpha t^2

   \theta= \dfrac{L}{I} t +\dfrac{1}{2}\dfrac{\tau}{I}t^2

   \theta= \dfrac{3}{0.14}\times 1.5+\dfrac{1}{2}\dfrac{-1.467}{0.14}\times 1.5^2

        θ = 20.35 rad

c) work done on the wheel

     W = τ x θ

     W = -1.467 x 20.35 rad

    W = -29.86 J

d) average power of wheel

    P_{av} =-\dfrac{W}{t}

    P_{av} =-\dfrac{(-29.86)}{1.5}

     P_{av} =19.91\ W          

7 0
3 years ago
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denis-greek [22]

Answer:

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