1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Roman55 [17]
3 years ago
15

1. Why did Asteroid 2019 OK cause concern among scientists? * The asteroid was not detected until it was extremely close to Eart

h. It's the largest known near-Earth asteroid ever discovered. The asteroid's path was aimed directly at the moon. The asteroid was too large to be deflected away from Earth
Physics
1 answer:
AveGali [126]3 years ago
7 0

Answer:

<u>The asteroid was not detected until it was extremely close to Earth. </u>

Explanation:

According to data from NASA, the Asteroid named 'Astriod 2019 OK', was detected when it was extremely close to earth with just about an estimated distance of  73,000 kilometers  (45,000 miles) from the Earth.

Scientists were concerned at the proximity of this space object to the Earth before it was discovered, and it brought about a cause of concern that since it was not extremely large (estimated 57 to 130 meters wide) it creates a potential for other smaller asteroids to escape detection and struck the earth.

You might be interested in
A centrifuge has an angular velocity of 3,000 rpm, what is the acceleration (in unit of the earth gravity) at a point with a rad
Anna71 [15]

Answer:

a_{r} = 1006.382g \,\frac{m}{s^{2}}

Explanation:

Let suppose that centrifuge is rotating at constant angular speed, which means that resultant acceleration is equal to radial acceleration at given radius, whose formula is:

a_{r} = \omega^{2}\cdot R

Where:

\omega - Angular speed, measured in radians per second.

R - Radius of rotation, measured in meters.

The angular speed is first determined:

\omega = \frac{\pi}{30}\cdot \dot n

Where \dot n is the angular speed, measured in revolutions per minute.

If \dot n = 3000\,rpm, the angular speed measured in radians per second is:

\omega = \frac{\pi}{30}\cdot (3000\,rpm)

\omega \approx 314.159\,\frac{rad}{s}

Now, if \omega = 314.159\,\frac{rad}{s} and R = 0.1\,m, the resultant acceleration is then:

a_{r} = \left(314.159\,\frac{rad}{s} \right)^{2}\cdot (0.1\,m)

a_{r} = 9869.588\,\frac{m}{s^{2}}

If gravitational acceleration is equal to 9.807 meters per square second, then the radial acceleration is equivalent to 1006.382 times the gravitational acceleration. That is:

a_{r} = 1006.382g \,\frac{m}{s^{2}}

6 0
3 years ago
What is the component in a car engine that would detect the need for air?​
Ipatiy [6.2K]

Answer:

Control of air–fuel ratio

Oxygen sensors tell the ECU whether the engine is running rich (too much fuel or too little oxygen) or running lean (too much oxygen or too little fuel) as compared to ideal conditions (known as stoichiometric).

Explanation:

4 0
3 years ago
Just wondering, what do you guys think the 5th dimension is? I've always believed it to be light.
zepelin [54]

Answer: In the 5th dimension, they who claim to know, say that there is only one time, including the past and the future.

8 0
3 years ago
To practice Problem-Solving Strategy 27.1: Magnetic Forces. A particle with mass 1.81×10−3 kgkg and a charge of 1.22×10−8 CC has
Roman55 [17]

Answer:

The magnitude of the acceleration  is a = 0.33 m/s^2

The direction is - \r k i.e the negative direction of the z-axis

Explanation:

 From  the question we are that

       The mass of the particle m = 1.8*10^{-3} kg

         The charge on the particle is q = 1.22*10^{-8}C

         The velocity is \= v = (3.0*10^4 m/s ) j

        The the magnetic field is  \= B = (1.63T)\r i + (0.980T) \r j

The charge experienced  a force which is mathematically represented as

         

                    F = q (\= v * \= B)

    Substituting value

         F = 1.22*10^{-8} (( 3*10^4 ) \r j \ \ X \ \  ( 1.63 \r i  + 0.980 \r j )T)

            = 1.22 *10^{-8} ((3*10^4 * 1.63)(\r j \ \  X \ \  \r i) + (3*10^4 * 0.980) (\r j \ \ X \ \  \r  j))

            = (-5.966*10^4 N) \r k

Note :

           i \ \ X \ \ j = k \\\\j \ \  X  \ \ k = i\\\\k  \ \ X \ \ i = j\\\\j \ \ X \ \ i = -k \\\\k \ \  X  \ \ j = -i\\\\i  \ \ X \ \ k = - j\\

Now force is also mathematically represented as

        F = ma

Making a the subject

      a = \frac{F}{m}

   Substituting values

     a =\frac{(-5.966*10^4) \r k}{1.81*10^{-3}}

        = (-0.33m/s^2)\r k

        = 0.33m/s^2 * (- \r k)

6 0
4 years ago
A warm-up is the exact same thing as a flexibility workout<br><br> True<br> False
kykrilka [37]
False :) ✨ got you my g
3 0
4 years ago
Other questions:
  • What does FCCLA stand for?
    15·2 answers
  • What law states that forces are equal in size and opposite direction
    13·1 answer
  • How long should a spring be stretched for it to store 45 J of energy? The force constant of the spring is
    6·1 answer
  • An antitank weapon fires a 3.00-kg rocket which acquires a speed of 50.0 m/s after traveling 90.0 cm down a launching tube. Assu
    8·1 answer
  • Problem 1.4 300 g of aluminum at 90°C is placed in a calorimeter cup containing 400 g of water. The mass of the copper calorimet
    14·1 answer
  • The venn diagram shown below compares the nuclear reactions in the sun and nuclear power plants.
    13·1 answer
  • a ball is thrown down at 25 m/s from a 500m tall building. how fast is it traveling when it hits the ground?
    12·1 answer
  • Will mark as BRAINLIEST.......
    12·2 answers
  • When the
    15·1 answer
  • Degrees of loudness and softness in music are called.
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!