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natita [175]
3 years ago
15

You stand 1.40 m in front of a wall and gaze downward at a small vertical mirror mounted on it. In this mirror you can see the r

eflection of your shoes. If your eyes are 1.70 m above your feet, through what angle should the mirror be tilted for you to see your eyes reflected in the mirror? (The location of the mirror remains the same, only its angle to the vertical is changed.)
Physics
1 answer:
Bess [88]3 years ago
7 0

Answer:

The angle is 31.26°.

Explanation:

Given that,

Distance = 1.40 m

Height = 1.70 m

We need to calculate the angle

Using formula of angle

tan\theta=\dfrac{y}{d}

Here, y = \dfrac{h}{2}

y=\dfrac{1.70}{2}=0.85\ m

Put the value into the formula

\tan\theta =\dfrac{0.85}{1.40}

\theta=\tan^{-1}0.6071

\theta=31.26^{\circ}

Hence, The angle is 31.26°.

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Determine the mass of the object below to the correct degree of precision.
Alinara [238K]

153.73 g.....................................

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3 years ago
A car moved 35 km to the South and Then 10 km to the North. What is its Displacement?
Harrizon [31]

Answer:

It's displacement would be 25 km.

Explanation:

That is because you would subtract 10 from 35 to get the distance away from the starting point.

3 0
3 years ago
The impulse of a constant force is equal to
Nookie1986 [14]

Answer:

Explanation:

It's equal to change of momentum in contact

6 0
4 years ago
A slanted vector has a magnitude of 41 N and is at an angle of 23 degrees north of east. What are the magnitude and direction of
jenyasd209 [6]

Answer:

The horizontal component is 37.74 N to east

The vertical component is 16.02 N to North

Explanation:

Any slant vector has two components

→ Horizontal component = R cos Ф

→ Vertical component = R sin Ф

→ R is the magnitude of the vector

→ Ф is the direction of the vector with positive part of the horizontal axis

A slanted vector has a magnitude of 41 N and is at an angle of 23

degrees north of east

23° north of east means the angle between the vector and the

east direction is 23° (east is the positive horizontal direction)

That means R is 41 N and Ф is 23°

→ R = 41 N , Ф = 23°

→ The horizontal component = 41 × cos(23) = 37.74 N east

→ The vertical component = 41 × sin(23) = 16.02 N North

<em>The horizontal component is 37.74 N to east</em>

<em>The vertical component is 16.02 N to North</em>

7 0
4 years ago
If a voltmeter has a less than ideal resistance, say 1 MΩ, and is used to measure the voltage across a resistor of a comparable
Naddik [55]

Answer:

As the difference between the resistance of voltmeter and the resistance being measured gets reduced the error in the reading of the voltmeter gets increased.

Explanation:

An ideal voltmeter has infinite parallel resistance and because of this it doesn't draw any current from the circuit of measurement which means it will measure the exact voltage across the elements.

But practically speaking, a real voltmeter doesn't has infinite resistance therefore, all the practical voltmeters face loading effect to some extent.

As the difference between the resistance of voltmeter and the resistance being measured gets reduced the error in the reading of the voltmeter gets increased. This is why we want to have a greater value of voltmeter resistance, ideally infinite so that the corresponding error is minimized.

Lets consider the given scenario,

A voltmeter has 1 MΩ parallel resistance and the resistance of of measuring element is 500 kΩ or 0.5 MΩ

lets suppose the supplied voltage is 1 V.

First lets assume that the voltmeter is ideal and it has infinite resistance, so in this case voltmeter will measure a voltage of 1 V across the 0.5 MΩ resistor.

Now consider the loading effect, when we connect the voltmeter across the 0.5 MΩ resistor they both become parallel so the resistance is

R = (1*0.5)/(1+0.5)

R = 0.33 MΩ

As you can see the voltmeter will see a reduced resistance and the corresponding voltage also reduces because resistance and voltage are directly proportional.

Therefore, it is preferred to have a very high parallel resistance of the voltmeter.

8 0
3 years ago
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