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natita [175]
3 years ago
15

You stand 1.40 m in front of a wall and gaze downward at a small vertical mirror mounted on it. In this mirror you can see the r

eflection of your shoes. If your eyes are 1.70 m above your feet, through what angle should the mirror be tilted for you to see your eyes reflected in the mirror? (The location of the mirror remains the same, only its angle to the vertical is changed.)
Physics
1 answer:
Bess [88]3 years ago
7 0

Answer:

The angle is 31.26°.

Explanation:

Given that,

Distance = 1.40 m

Height = 1.70 m

We need to calculate the angle

Using formula of angle

tan\theta=\dfrac{y}{d}

Here, y = \dfrac{h}{2}

y=\dfrac{1.70}{2}=0.85\ m

Put the value into the formula

\tan\theta =\dfrac{0.85}{1.40}

\theta=\tan^{-1}0.6071

\theta=31.26^{\circ}

Hence, The angle is 31.26°.

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2) Two railway tracks are parallel to west east direction. Along one track, train A moves with a speed of 45 m/s from
Natalija [7]

Answer:

105 m/s

Explanation:

Given that the speed of train A, V_A = 45 m/s from west to east.

Speed of train B, V_B = 60 m/s from east to west.

Train B is moving in the opposite direction with respect to the speed of train A. Assuming that the speed from east to west direction is positive.

So, the speed of train A from east to west= - 45 m/s

The speed of train B w.r.t train A = V_B - V_A=60-(-45)=60+45=105 m/s

Hence, the speed of train B w.r.t train A is 105 m/s from east to west.

5 0
3 years ago
A car moving with an initial speed v collides with a second stationary car that is one-half as massive. After the collision the
Mashutka [201]

Answer:

4v/3

Explanation:

Assume elastic collision by the law of momentum conservation:

m_1v = m_1v_1 + m_2v_2

where v is the original speed of car 1, v1 is the final speed of car 1 and v2 is final speed of car 2. m1 and m2 are masses of car 1 and car 2, respectively

Substitute m_2 = m_1/2 \& v_1 = v/3

m_1v = \frac{m_1v}{3} + \frac{m_1v_2}{2}

Divide both side by m_1, then multiply by 6 we have

6v = 2v + 3v_2

3v_2 = 4v

v_2 = \frac{4v}{3}

So the final speed of the second car is 4/3 of the first car original speed

5 0
3 years ago
A tennis ball travelling at a speed of 46m/s with a mass of 58kg. Calculate the kinetic<br>energy​
Zanzabum

Answer:

its 1/2 the mass of the object times by its velocity ^ 2

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Newton's second law problem. The spring constant can be determined from the balance of forces in equilibrium. Suppose the spring
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Answer:

K =6.697 Kg/s²

Explanation:

Given:

delta m =41 g = 0.041 kg

delta x = 6cm = 0.06m

g = 9.8 m/s²

according to the given formula

K = delta m g /delta x

K = (0.041 kg × 9.8 m/s²) / 0.06m

K =6.697 Kg/s²

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3 years ago
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1. friction between water molecules
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