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maks197457 [2]
3 years ago
8

The mass number of an isotope of uranium is 238, and its atomic number is 92. Which symbol best represents this isotope of urani

um?
Chemistry
2 answers:
AURORKA [14]3 years ago
7 0

Answer: The isotope will be represented  by symbol ^{238}_{92}U .

Solution:

The isotope of an element is represented by:

^{A}_{Z}X

X = Symbol of an element

Z = Atomic Number of that element = Total number of electrons or protons

A = atomic mass of that element = Z+ total number of neutrons

So the uranium isotope with atomic mass of 238 and atomic number of 92 will be written as:

^{238}_{92}U

laila [671]3 years ago
5 0
238_{U}



That is a capital U with the number 238 at upper left of the letter

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When the temperature of a sample of liquid increases , what else increases ?
Lubov Fominskaja [6]

Answer:

Its kinetic energy.

Explanation:

In a liquid, the molecules are so close together that there is very little empty space. A liquid also has a definite volume, because molecules in a liquid do not break away from the attractive forces. The molecules can, however, move past one another freely, and so a liquid can flow, can be poured, and assumes the shape of its container.

An increase in the temperature of a liquid causes an increase in the average speed of its molecules. As the temperature of a liquid increases, the molecules move faster thereby increasing the liquid's kinetic energy.

5 0
3 years ago
If you have 222 g of radioisotope with a half-life of 5 days, how much isotope would remain after 15 days?
Dima020 [189]
If the half life is 5 days, you would have to divide 222 by 2 3 times.
so 222/2 =111g
111/2 = 55.5g
55.5/2 = 27.75g

after four half life the mass would be
27.75/2
13.875g

the percent would be
13.875/222
= 6.25%
7 0
3 years ago
Use the following half-reactions to construct a voltaic cell:
velikii [3]

<u>Answer:</u> The correct answer is 3Ag^+(aq.)+Cr(s)\rightarrow 3Ag(s)+Cr^{3+}(aq.);E^o_{cell}=+1.53V

<u>Explanation:</u>

We are given:

Cr^{3+}(aq.)+3e^-\rightarrow Cr(s);E^o=-0.73V\\\\Ag^+(aq.)+e^-\rightarrow Ag(s);E^o=+0.80V

The substance having highest positive E^o potential will always get reduced and will undergo reduction reaction. Here, silver will always undergo reduction reaction will get reduced.

Chromium will undergo oxidation reaction and will get oxidized.

The half reactions for the above cell is:

Oxidation half reaction: Cr(s)\rightarrow Cr^{3+}+3e^-;E^o_{Cr^{3+}/Cr}=-0.73V

Reduction half reaction: Ag^{+}+e^-\rightarrow Ag(s);E^o_{Ag^{+}/Ag}=0.80V       ( × 3)

Net equation:  3Ag^+(aq.)+Cr(s)\rightarrow 3Ag(s)+Cr^{3+}(aq.)

Oxidation reaction occurs at anode and reduction reaction occurs at cathode.

To calculate the E^o_{cell} of the reaction, we use the equation:

E^o_{cell}=E^o_{cathode}-E^o_{anode}

Putting values in above equation, we get:

E^o_{cell}=0.80-(-0.73)=1.53V

Hence, the correct answer is 3Ag^+(aq.)+Cr(s)\rightarrow 3Ag(s)+Cr^{3+}(aq.);E^o_{cell}=+1.53V

4 0
3 years ago
For the reaction represented by the equation 
2Fe + O2 → 2FeO, how many moles of iron oxide will be produced from 8.00 mol of ir
STatiana [176]

Answer:

8.00 moles.

Explanation:

The ratio of Fe to FeO  is 2:2 = 1:1,  so 8 moles are produced.

8 0
3 years ago
1 x 10^-3 m is the same as which of the following? Select all that apply.
Yuri [45]

Answer: b and d

Explanation:

1×10^-3=1×1/10³=1×1/1000=1/1000 so b is correct

1×10^-3=1/1000=0.001

so d is correct

8 0
2 years ago
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