Answer: There are 0.0129 moles of silver present in 1.4 grams of silver (Ag).
Explanation:
Given: Mass of silver = 1.4 g
Number of moles is the mass of substance divided by its molar mass.
As molar mass of silver is 107.86 g/mol. Therefore, moles of silver are calculated as follows.
Thus, we can conclude that there are 0.0129 moles of silver present in 1.4 grams of silver (Ag).
Answer:
HBr(aq) + LiOH(aq) = LiBr(aq) + H2O(l)
Explanation:
For this reaction, the reactants are the hydrobomic acid and the lithium hydroxide which produces the products lithium bromide and water.
We need to separate different components of a mixture to separate the useful components from the non-useful or some harmful components.
Examples:
(a) Tea leaves are separated from tea.
(b) Pebbles are separated form rice and pulse.
I believe KI is not a a binary molecule.
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The percent abundance in the container by bean will be 43.33 % if there are 10 navy beans, 3 pinto beans, and 17 lentils in a container
<h3>What is Percentage composition ?</h3>
The percentage composition of a given compound is defined as the ratio of the amount of each element to the total amount of individual elements present in the compound multiplied by 100.
% composition by bean = number of beans / total number of objects in container x 100
- Total object = 10 ( navy beans) + 3 (pinto beans) + 17 ( lentils) = 30 objects
- Total beans = 10 ( navy beans) + 3 (pinto beans) = 13 beans
hence ;
- % composition by beans = 13/30 x 100 = 43.33 %
Therefore, the percent composition of the container by bean is 43.33 %
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