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Arte-miy333 [17]
3 years ago
9

the two forces acting on a falling object are gravity and?....1.force, 2. friction, 3. air resistance, and 4. net force?​

Physics
1 answer:
Vsevolod [243]3 years ago
6 0
In free fall, the only force acting on an object is gravity. The force of gravity is an unbalanced force, which causes an object to accelerate. In the absence of air, two objects with different masses fall at exactly the same rate of acceleration.
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A woman at an airport is towing her 20.0-kg suitcase at constant speed by pulling on a strap at an angle θ above the horizontal.
Elza [17]

Answer:

Normal force: 167.48 N

Explanation:

  • First of all it is necessary to draw the free body diagram of the suitcase adding alll the forces stated on the question: the normal force, the friction force and pull force exterted by the woman. Additionally, we need to add the weight, the forces exerted by Earth's gravity. I attached the diagram so you can check it.
  • We need to resolve all the unknown quantities on this exercise, so we need to write down the sum of forces equations on X-Axis and Y-axis. Remember that force exerted by the woman has an angle with respect the horizontal (X-Axis),  that is to say it has force compoents on both X and Y axis.  The equations  will be equal to zero since the suitcase  is at constant speed (acceleration is zero).

        ∑F_{x}:  F{x}-20 = 0  

        ∑F_{y}: N -W+F_{y}=0

  • Our objetive is to find the value of the normal force. It means we can solve the sum of Y-axis for N. The solution would be following:

       N = W - Fy

  • Keep in mind Weight of the suitcase (W) is equal to the suitcase mass times the acceleration caused by gravity (9.81\frac{m}{s^{2}}. Furthermore, Fy can be replaced using trigonometry as Fsin(\theta) where θ is the angle above the horizontal. So the formula can be written in this way:

        N = mg -Fsin(\theta)

  • We need to find the value of θ so we can find the value of N. We can find it out solving the sum of forces on X-axis replacing <em>Fx</em> for Fcos(θ). The equation will be like this:

        Fcos(\theta) -20 = 0   ⇒   Fcos(\theta) = 20\theta                            [tex]\theta=cos^{-1}(20/F)

  • Replacing the value of F we will see θ has a value of 55.15°. Now we can use this angle to find the value of N. Replacing mass, the gravity acceleration and the angle by their respective values, we will have the following:

       N = 20 x 9.81 - 35sin(55.15)  ⇒ N = 167.48 N

7 0
3 years ago
What would the final volume of 40 L of gas at 80 pascals be if the pressure increases to 130 pascals?
melomori [17]

Answer:

Final volume, V2 = 24.62 L

Explanation:

Given the following data;

Initial volume = 40 L

Initial pressure = 80 Pa

Final pressure = 130 Pa

To find the final volume V2, we would use Boyles' law.

Boyles states that when the temperature of an ideal gas is kept constant, the pressure of the gas is inversely proportional to the volume occupied by the gas.

Mathematically, Boyles law is given by;

PV = K

P_{1}V_{1} = P_{2}V_{2}

Substituting into the equation, we have;

80 * 40 = 130V_{2}

3200 = 130V_{2}

V_{2} = \frac {3200}{130}

V_{2} = 24.62

Final volume, V2 = 24.62 Liters

5 0
3 years ago
PLEASE HELP!!! 25 pts!!
mina [271]

Answer:

The slope of the graph is what you need. That tells you the speed not the velocity. In order to find the velocity you would also need to know the direction of the motion.

3 0
3 years ago
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Mr. Phillips' car is parked on a steep hill with the brakes applied and the engine off. Because of the car's position, it has gr
aivan3 [116]

Answer:

The anser is b

Explanation:

4 0
3 years ago
A car goes from 0 to 26.8 m/s in 6.2 s. What is the average acceleration of the car?
Nutka1998 [239]

Answer:

0 - 60 mph = 0 - 26.8 m/s = 0 - 96.6 km/h; 0 - 100 km/h = 0 - 27.8 m/s = 0 - 62.1 mph.

Explanation:

5 0
3 years ago
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