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zmey [24]
2 years ago
7

The engine of a 550kg car is producing a net force of 11,000N. What is its acceleration?

Physics
2 answers:
Fudgin [204]2 years ago
8 0

Answer:

20

Explanation:

(correct me if im wrong)

F = m×a

11000 = 550 × a

11000/550 = a

Acceleration =20

finlep [7]2 years ago
7 0

Answer:

Yeda

Explanation:

yshyei5rexwu drift hai used thakare I exam rest watu testing reddy

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A car is moving South at a constant speed of 60 miles per hour. The force of the
Anastaziya [24]

Answer: 750 N

Explanation:

The net force is 1200 - 450 = 750 N

As we are told the speed is constant, then this force must be increasing the car's potential energy by climbing a hill.

F = mgsinθ

If we knew the car mass, we could find the hill slope angle.

If we knew the hill slope angle, we could find the car mass.

6 0
2 years ago
Air expands adiabatically in a piston–cylinder assembly from an initial state where p1 = 100 lbf/in.2, v1 = 3.704 ft3/lb, and T1
lutik1710 [3]

Answer:

Final temperature is equal to 1291.63°R  

Explanation:

given,

p₁ = 100 lb f/in²,               v₁ = 3.704 ft³/lb,           and T₁ = 1000 °R

p₂ = 30 lb f/in²                 n = 1.4

Δ u = 0.171(T₂ - T₁)

we know for poly tropic process

p vⁿ = constant

p₁ v₁ⁿ = p₂ v₂ⁿ

100 × 3.704¹°⁴ = 30 × v₂¹°⁴

v₂ = 8.753 ft³/lb

work done for poly tropic process

W = \dfrac{p_1v_1-p_2v_2}{n-1}

    = \dfrac{100\times 3.704-30\times 8.753}{1.4-1}

    = 269.525 lbf/in².ft³

W = \dfrac{269.525}{5.40395} Btu/lb

   = 49.87 Btu/lb

in the piston cylinder arrangement air is expanding acrobatically

Δ q = Δu + w

Δ u = - w

0.171(T₂ - T₁) = -49.87

0.171(T₁ - T₂) = -49.87

0.171 T₂ = 0.171 × 1000 + 49.87

T₂ = 1291.63 °R

Final temperature is equal to 1291.63°R  

5 0
2 years ago
How does the entropy of steam compare to the entropy of ice?
Dmitriy789 [7]

The answer is; The entropy of steam is larger than because it is more disordered than ice

Entropy is synonymous to the degree of disorder or randomness of molecules in a system. The molecules of steam are far apart from each other and move randomly in the system colliding with each other. Those of ice has less kinetic energy, vibrate more or less in a fixed position in the structiure, and are arranged in a orderd fashion


3 0
3 years ago
Read 2 more answers
How does inertia affect a person who is not wearing a seatbelt during a collision?
Vadim26 [7]
When someone fails to wear a seat belt the passenger becoming a projectile the force a person will be subjected to for a passenger weighting 100 pounds, and the car is traveling at 60 mph would be the same as 6000 pounds. thats like hitting a brick wall. so is other words put ur seat belt on. 

hope this helped (:
4 0
3 years ago
An airliner arrives at the terminal, and its engines are shut off. The rotor of one of the engines has an initial clockwise angu
Ilia_Sergeevich [38]

(a) 1200 rad/s

The angular acceleration of the rotor is given by:

\alpha = \frac{\omega_f - \omega_i}{t}

where we have

\alpha = -80.0 rad/s^2 is the angular acceleration (negative since the rotor is slowing down)

\omega_f is the final angular speed

\omega_i = 2000 rad/s is the initial angular speed

t = 10.0 s is the time interval

Solving for \omega_f, we find the final angular speed after 10.0 s:

\omega_f = \omega_i + \alpha t = 2000 rad/s + (-80.0 rad/s^2)(10.0 s)=1200 rad/s

(b) 25 s

We can calculate the time needed for the rotor to come to rest, by using again the same formula:

\alpha = \frac{\omega_f - \omega_i}{t}

If we re-arrange it for t, we get:

t = \frac{\omega_f - \omega_i}{\alpha}

where here we have

\omega_i = 2000 rad/s is the initial angular speed

\omega_f=0 is the final angular speed

\alpha = -80.0 rad/s^2 is the angular acceleration

Solving the equation,

t=\frac{0-2000 rad/s}{-80.0 rad/s^2}=25 s

6 0
3 years ago
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