In physics, work is equal to the product of force and distance, given that the direction of force is the same with the direction of the distance.
W = Fd
The total force is
F = 1,700 N + 500 N = 2,200 N
Now, if the question is the work needed to lift the barbell from the ground, the distance would be 2 m. Hence, the work would be
W = (2,220 N)(2 m) = 4,400 N·m or 4,400 J
Answer:
Step-by-step explanation:
The computation of the volume of the cylinder is shown below:
As we know that
The Volume of the cylinder is
= base × height
= (4x)^2 + (5x)^2
=16x^2 + 25x^2
= 41x^3
Hence, the volume of the cylinder is 41x^3
Answer:
Hence the function which has the smallest minimum is: h(x)
Step-by-step explanation:
We are given function f(x) as:
- f(x) = −4 sin(x − 0.5) + 11
We know that the minimum value attained by the sine function is -1 and the maximum value attained by sine function is 1.
so the function f(x) receives the minimum value when sine function attains the maximum value since the term of sine function is subtracted.
Hence, the minimum value of f(x) is: 11-4=7 ( when sine function is equal to 1)
- Also we are given a table of values for function h(x) as:
x y
−2 14
−1 9
0 6
1 5
2 6
3 9
4 14
Hence, the minimum value attained by h(x) is 5. ( when x=1)
- Also we are given function g(x) ; a quadratic function passing through (2,7),(3,6) and (4,7)
so, the equation will be:
Hence on putting these coordinates we will get:
a=1,b=3 and c=7.
Hence the function g(x) is given as:

So,the minimum value attained by g(x) could be seen from the graph is at the point (3,6).
Hence, the minimum value attained by g(x) is 6.
Hence the function which has the smallest minimum is h(x)
It would be FH
A diameter is basically the length of the line through the centre that touches 2 points on a circles edges
Answer:
Step-by-step explanation:
If the expression contains 3 terms none of which can combine with any other, the the expression is a Trinomial. An example of such a thing is f(x) = x^2 + 2x + 1.
The x cannot combine with the x^2 nor with the 1. The same can be said for the x^2 and the 1.