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GenaCL600 [577]
3 years ago
6

A mixture of nitrogen gas and oxygen gas has a total pressure of l.13 atm. If the partial pressure of oxygen is 0.43 atm, what i

s the partial pressure of nitrogen?
a) 1.56 atm
b) 1.13 atm
c) 0.70 atm
d) 0.38 atm​

Chemistry
2 answers:
Vladimir [108]3 years ago
8 0
C
0.70

I hope this is help, I’m so so sorry if I’m incorrect
Stels [109]3 years ago
6 0

Answer:

0.70 atm - Option C

Explanation:

Let's apply the mole fraction concept to solve this:

Partial pressure of a gas / Total pressure = Mole fraction of a gas.

In a mixture, sum of mole fraction from each gas = 1

Partial pressure of O₂ / Total pressure = Mole fraction of O₂

0.43 atm / 1.13 atm = 0.380

1 - 0.380 = 0.62 → Mole fraction N₂

Mole fraction N₂ = Partial pressure N₂ / Total pressure

0.62 = Partial Pressure N₂ / 1.13 atm

0.62 . 1.13 = 0.70 atm → Partial Pressure N₂

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Answer:

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Explanation:

<u>Given the following data;</u>

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Mathematically, Heat capacity is given by the formula;

Q = MCT

Where;

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Making "M" the subject of formula, we have;

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A chemist must prepare 300.0mL of nitric acid solution with a pH of 0.70 at 25°C. He will do this in three steps: Fill a 300.0mL
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<u>Answer:</u> The volume of concentrated solution required is 9.95 mL

<u>Explanation:</u>

To calculate the pH of the solution, we use the equation:

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Putting values in above equation, we get:

0.70=-\log[H^+]

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1 mole of nitric acid produces 1 mole of hydrogen ions and 1 mole of nitrate ions.

Molarity of nitric acid = 0.199 M

To calculate the volume of the concentrated solution, we use the equation:

M_1V_1=M_2V_2

where,

M_1\text{ and }V_1 are the molarity and volume of the concentrated nitric acid solution

M_2\text{ and }V_2 are the molarity and volume of diluted nitric acid solution

We are given:

M_1=7.0M\\V_1=?mL\\M_2=0.199M\\V_2=350mL

Putting values in above equation, we get:

7.0\times V_1=0.199\times 350.0\\\\V_1=\frac{0.199\times 350}{7.0}=9.95mL

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