A mixture of nitrogen gas and oxygen gas has a total pressure of l.13 atm. If the partial pressure of oxygen is 0.43 atm, what i
s the partial pressure of nitrogen?
a) 1.56 atm
b) 1.13 atm
c) 0.70 atm
d) 0.38 atm
a) 1.56 atm
b) 1.13 atm
c) 0.70 atm
d) 0.38 atm
2 answers:
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Answer:
0.7457 g is the mass of the helium gas.
Explanation:
Given:
Pressure = 3.04 atm
Temperature = 25.0 °C
The conversion of T( °C) to T(K) is shown below:
T(K) = T( °C) + 273.15
So,
T₁ = (25.0 + 273.15) K = 298.15 K
Volume = 1.50 L
Using ideal gas equation as:
where,
P is the pressure
V is the volume
n is the number of moles
T is the temperature
R is Gas constant having value = 0.0821 L.atm/K.mol
Applying the equation as:
3.04 atm × 1.50 L = n × 0.0821 L.atm/K.mol × 298.15 K
<u>⇒n = 0.1863 moles</u>
Molar mass of helium = 4.0026 g/mol
The formula for the calculation of moles is shown below:
Thus,
<u>0.7457 g is the mass of the helium gas. </u>