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Rudik [331]
3 years ago
9

Which statement best explains the difference between polar and nonpolar covalent bonds?(1 point)

Chemistry
2 answers:
Mars2501 [29]3 years ago
8 0

Answer:

Let me help you out fr:

Explanation:

1. 0.5 to 1.7

2. fluorine (F)

3. KNO3

4. Polar covalent bonds share electrons unequally, while nonpolar covalent bonds share electrons equally.

5. Fe and S have an ionic bond, while S and O have covalent bonds.

miv72 [106K]3 years ago
6 0

Answer:

Answer is 4

Explanation:

Polar covalent bonding is a type of chemical bond where a pair of electrons is unequally shared between two atoms. ... If the electronegativity of two atoms is basically the same, a nonpolar covalent bond will form, and if the electronegativity is slightly different, a polar covalent bond will form.

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How many moles are equal to 4.15x10^23 molecules of carbon monoxide?
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To be able to determine the number of moles that a certain number of molecules comprises, we simply divide the number of molecules by the Avogadro's number which is equal to 6.022 x 10^23. 

   n = M/A

where n is the number of moles, M is the number of molecules, and A is Avogadro's number. Substituting the known values,

   n = (4.15 x 10^23 molecules)/(6.022 x 10^23 molecules/mol)

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<em>Answer: 0.689 moles</em>

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3 years ago
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An atom of sodium has 11 protons, 11 electrons,and 12 neutrons, what is its atomic number and mass number?
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What nevres carrys information from the hairs inside the cochlea?
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How does the ribosome know the sequence of amino acids
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3 years ago
A 20g sample of iron at a temperature of 120oC is placed into a container of water. There are 300 milliliters of water in the co
galben [10]

Answer:

30.63 °C will be the final temperature of the water.

Explanation:

Heat lost by iron will be equal to heat gained by the water

-Q_1=Q_2

Mass of iron = m_1=20 g

Specific heat capacity of iron = c_1=0.444 J/g^oC

Initial temperature of the iron = T_1=120^oC

Final temperature = T_2=T

Q_1=m_1c_1\times (T-T_1)

Volume of water = 300 ml

Density of water = 1 g/mL

Mass of water= m_2=300 mL\times 1 g/mL = 300 g

Specific heat capacity of water= c_2=4.184 J/g^oC

Initial temperature of the water = T_3=30^oC

Final temperature of water = T_2=T

Q_2=m_2c_2\times (T-T_3)

-Q_1=Q_2

-(m_1c_1\times (T-T_1))=m_2c_2\times (T-T_3)

On substituting all values:

we get, T =  30.63°C

30.63 °C will be the final temperature of the water.

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3 years ago
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